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rosijanka [135]
3 years ago
10

A company is setting up offices in two different cities. The number of employees hired by the company for its office in city A o

ver x months is given by the function f(x) = 9x.
The number of employees hired by the company for its office in city B over x months is given by the function g(x) = 3(2)x.

Which function best describes the total number of employees in the company over x months, and after how many months will the total number of employees be 141?

h(x) = 3(3x + (2)x); 5 months
h(x) = 3(2x + (3)x); 2 months
h(x) = 2(3x + 3(2)x); 4 months
h(x) = 3x + (2)x; 6 months
Mathematics
2 answers:
MariettaO [177]3 years ago
4 0
The funcyion for the problem is
h(x) = 3(3x + (2)x);
5 months
labwork [276]3 years ago
3 0
For this case we have the following functions:
 City A:
 f (x) = 9x
 City B:
 g (x) = 3 (2) ^ x
 The total number of employees will be:
 h (x) = f (x) + g (x)
 Substituting we have:
 h (x) = 9x + 3 (2) ^ x
 Rewriting we have:
 h (x) = 3 (3x + (2) ^ x)
 For 5 months we have:
 h (5) = 3 * (3 * (5) + (2) ^ 5)
 h (5) = 141
 Answer:
 the total number of employees in the company over x months and the total number of employees will be 141 when the function is:
 h (x) = 3 (3x + (2)^x); 5 months
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A linear sequence starts a+3b a+7b a+11b the 2nd term has value 19 the 5th term has value 67 work out the values of a and b
alekssr [168]

Answer:

a = -9

b = 4

Step-by-step explanation:

Given

Sequence: a+3b, a+7b, a+11b

2nd term = 19

5th term = 67

Required

Find a and b

First, the 5th term needs to be calculated;

Using formula for Arithmetic Progression (AP), the formula goes thus

T_n = T_1 + (n - 1)d

Where n = 5

T_1 = a + 3b ------------ FIrst term

d = T_2 - T_1 or T_3 - T_2 --- Difference between two successive terms

d = a + 7b - (a + 3b)

d = a + 7b -a - 3b

d = a - a + 7b - 3b

d = 4b

So, T_n = T_1 + (n - 1)d becomes

T_5 = a + 3b + (5 - 1)4b

T_5 = a + 3b + (4)4b

T_5 = a + 3b + 16b

T_5 = a + 19b

Now that we have values for 2nd and 5th term;

From the second, T2 = 19 and T5 = 67

This gives

a + 7b = 19 --- Equation 1

a + 19b = 67 ---- Equation 2

Make a the subject of formula in (1)

a = 19 - 7b

Substitute these values in equation 1

a + 19b = 67 becomes

19 - 7b + 19b = 67

19 + 12b = 67

Collect like terms

12b= 67 - 19

12b = 48

Divide both sides by 12

\frac{12b}{12} = \frac{48}{12}

b = 4

Recall that b = 4

Substitute a = 19 - 7b and nothing will hire

a = 19 - 7(4)

a = 19 - 28

a = -9

Hence, the values of a and b are -9 and 4 respectively.

5 0
3 years ago
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