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pantera1 [17]
4 years ago
14

Figure ABCD has vertices A(−4, 1), B(2, 1), C(2, −5), and D(−4, −3). What is the area of figure ABCD?

Mathematics
1 answer:
Andrej [43]4 years ago
6 0

Answer:

24

Step-by-step explanation:

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Ben rode his bike 3 miles today. Tomorrow he plans to ride 13 times as far. In this equation, n represents the number of miles B
olga2289 [7]

Answer

n=45 miles

Step-by-step explanation:

5 0
3 years ago
Multiple Response: Please select all correct answers and click "submit." Which of the following are among the five basic postula
Kazeer [188]

To Euclid, a postulate is something that is so obvious it may be accepted without proof.

A. A straightedge and compass can be used to create any figure.

That's not Euclid, that's just goofy.

B. A straight line segment can be drawn between any two points.

That's Euclid's first postulate.

C. Any straight line segment can be extended indefinitely.

That's Euclid's second postulate.

D. The angles of a triangle always add up to 180.

That's true, but a theorem not a postulate. Euclid and the Greeks didn't really use degree angle measurements like we do. They didn't really trust them, I think justifiably. Euclid called 180 degrees "two right angles."

Answer: B C

4 0
3 years ago
Help me please! Did I do this right?​
MrMuchimi

Answer:

no its A and B

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
1. 15<br> 2. 27<br> 3. 75<br> 4. 87
masya89 [10]
I’m 15 so the answer is number 1
3 0
3 years ago
In terms of the trigonometric ratios for ΔABD, what is the length of line segment BD?
erica [24]

In terms of the trigonometric ratios for ΔABD, what is the length of line segment BD?

Answer:

BD = c*sin(A)

BD = c*cos(B)

BD = b*tan(A)

Step-by-step explanation:

∆ABD is a right triangle.

Recall: trigonometric ratios of any right triangle can easily be understood or remembered with the acronym, SOHCAHTOA.

SOH => sin(θ) = opposite/hypotenuse

CAH => Cos(θ) = adjacent/hypotenuse

TOA = tan(θ) = opposite/adjacent

Thus, the length of segment BD, in terms of trigonometric ratios for ∆ABD can be done as follows:

Let BD = x

AB = c

AD = b

=>The sine ratio for the length of line segment BD = x, using SOH.

θ = A

Opposite = DB = x

hypotenuse = AB = c

sin(A) = \frac{x}{c}

Make x the subject of formula.

c*sin(A) = x

BD = x = c*sin(A)

=>The Cosine ratio for the length of line segment BD = x, using CAH

θ = B

Adjacent = DB = x

hypotenuse = AB = c

cos(B) = \frac{x}{c}

Make x the subject of formula.

c*cos(B) = x

BD = x = c*cos(B)

=>The Tangent ratio for the length of line segment BD = x, using TOA

θ = A

Adjacent = DB = x

hypotenuse = AD = b

tan(A) = \frac{x}{b}

Make x the subject of formula.

b*tan(A) = x

BD = x = b*tan(A)

5 0
3 years ago
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