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Ksju [112]
2 years ago
14

Jessle served 11 pints of orange Juice at her party. How many quarts of orange juice did she serve?​

Mathematics
1 answer:
Ratling [72]2 years ago
6 0
5.5 quarts


(Divide the volume value by 2)
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Consider the given function and the given interval. f\(x\) = 2 sin\(x\) - sin\(2 x\) text(, ) [0 text(, ) pi] (a) Find the avera
Finger [1]

a. The average value of f on the given interval is

\displaystyle f_{\rm ave}=\frac1{\pi-0}\int_0^\pi(2\sin x-\sin2x)\,\mathrm dx=\boxed{\frac4\pi}

b. Solve for c:

\dfrac4\pi=2\sin c-\sin2c\implies\boxed{c\approx1.238\text{ or }c\approx2.808}

4 0
3 years ago
There are approximately 15 milliliters (mL) in 1 tablespoon (tbsp). Which expression can be used to find the approximate number
Greeley [361]
We develop the ratio between the number of milliliters present in 1 tablespoon and that is,
                               15 mL: 1 tablespoon
We let x be the number of millileter in 3 tbsp and it can be determined through the equation below.
                                x = 3 tbsp x (15 mL/ 1 tbsp) = 45 mL
Therefore, there are 45 mL in 3 tbsp.
3 0
3 years ago
Estimate 8978 x 38 by first rounding each number so that it has only 1 nonzero digit.​
Afina-wow [57]

Answer:

9,000 x 40 = 360,000

Step-by-step explanation:

9,000 x 40 = 360,000

A one nonzero digit is a number that has only one number that's not 0. For example, 300 has only one nonzero digit.

Hope this helps!

6 0
2 years ago
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zvonat [6]

i would probably  use an iv or a blood simple

3 0
3 years ago
A spring exerts a force of 6 N when stretched 3 m beyond its natural length. How much work is required to stretch the spring 2 m
lys-0071 [83]

Answer:

4Joules

Step-by-step explanation:

According to Hooke's law which states that extension of an elastic material is directly proportional to the applied force provide that the elastic limit is not exceeded. Mathematically,

F = ke where

F is the applied force

K is the elastic constant

e is the extension

If a spring exerts a force of 6 N when stretched 3 m beyond its natural length, its elastic constant 'k'

can be gotten using k = f/e where

F = 6N, e = 3m

K = 6N/3m

K = 2N/m

Work done on an elastic string is calculated using 1/2ke².

If the spring is stretched 2 m beyond its natural length, the work done on the spring will be;

1/2× 2× (2)²

= 4Joules

3 0
3 years ago
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