Answer:
The height of the cross section is ![4\ ft](https://tex.z-dn.net/?f=4%5C%20ft)
Step-by-step explanation:
we know that
The area of trapezoid is equal to
![A=\frac{1}{2}(b1+b2)h](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%28b1%2Bb2%29h)
In this problem we have
![A=76\ ft^{2}](https://tex.z-dn.net/?f=A%3D76%5C%20ft%5E%7B2%7D)
![b1=34\ ft](https://tex.z-dn.net/?f=b1%3D34%5C%20ft)
![b2=4\ ft](https://tex.z-dn.net/?f=b2%3D4%5C%20ft)
substitute and solve for h
![76=\frac{1}{2}(34+4)h](https://tex.z-dn.net/?f=76%3D%5Cfrac%7B1%7D%7B2%7D%2834%2B4%29h)
![152=(38)h](https://tex.z-dn.net/?f=152%3D%2838%29h)
![h=152/38=4\ ft](https://tex.z-dn.net/?f=h%3D152%2F38%3D4%5C%20ft)
this should help I have it step
Answer:
g = -0.8571428571
Step-by-step explanation:
3g + -9 + 11g + 21 = 0
Reorder the terms:
-9 + 21 + 3g + 11g = 0
Combine like terms: -9 + 21 = 12
12 + 3g + 11g = 0
Combine like terms: 3g + 11g = 14g
12 + 14g = 0
Solving
12 + 14g = 0
Solving for variable 'g'.
Move all terms containing g to the left, all other terms to the right.
Add '-12' to each side of the equation.
12 + -12 + 14g = 0 + -12
Combine like terms: 12 + -12 = 0
0 + 14g = 0 + -12
14g = 0 + -12
Combine like terms: 0 + -12 = -12
14g = -12
Divide each side by '14'.
g = -0.8571428571
Simplifying
g = -0.8571428571