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jolli1 [7]
3 years ago
8

Please help! First answer that is correct wins Brainliest!​

Mathematics
2 answers:
damaskus [11]3 years ago
5 0

Answer:

yes it is. flip the triangle over it has a right side

Lady_Fox [76]3 years ago
4 0
Yes because it has a right angle
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Find the x- and y-intercept of the line. <br><br> –3x + 9y = 18
Mnenie [13.5K]
Line <span>–3x + 9y = 18
</span>
x-intercept when y = 0
so -3x = 18
        x = -6

y-intercept when x = 0
so 9y = 18
       y = 2

answer
x-intercept (-6,0)
y-intercept (0, 2)

hope it helps
4 0
3 years ago
Is the proportion A, B, D, or D?
Oksanka [162]

Answer:

C.)

Step-by-step explanation:

4/20=8/x

3 0
3 years ago
If line t is a transversal of lines l and m, name the angle relationship of the given angle pairs.
Ghella [55]

Answer:

\angle 1\ and\ \angle 3 are corresponding angles and are congruent to each other.

\angle 8\ and\ \angle 4 are alternate exterior angles and thus congruent to each other.

\angle 2\ and\ \angle 3 are interior angles on the same side, and they are supplementary(sum=180°).

Step-by-step explanation:

Given:

Line l\parallel m

Line t is traversal.

By angle properties we can name the angle relationship of given angle pairs.

\angle 1\ and\ \angle 3 are corresponding angles and are congruent to each other.

\angle 8\ and\ \angle 4 are alternate exterior angles and thus congruent to each other.

\angle 2\ and\ \angle 3 are interior angles on the same side, and thus they are supplementary.

8 0
3 years ago
Which of the four representations are incorrect?
Schach [20]
Y=6x + 27 isn’t right
4 0
3 years ago
Read 2 more answers
Suppose an isosceles triangle ABC has A = 45° and b = c = 4. What is the length of a^2?
Mila [183]
Since b = c, the angles B and C are congruent.
180 - 45 = 135
135/2 = =67.5

A = 45
B = 67.5
C = 67.5
a = ?
b = 4
c = 4

Since we know two sides and all three angles, we can use the law of sines to find a.

b/sin B = a/sin A

4/(sin 67.5) = a/(sin 45)

a = 4(sin 45)/(sin 67.5)

a^2 = (4(sin 45)/(sin 67.5))^2

a^2 = 9.37
4 0
4 years ago
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