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insens350 [35]
3 years ago
11

The basketball team is playing in the championship game and wants to take a bus filled with family and friends to cheer for the

players. The bus will cost a total of $90, and each ticket to the game will cost $2. What is the maximum number of people that the team can take without exceeding their budget of $160?
Mathematics
1 answer:
sergij07 [2.7K]3 years ago
6 0

Answer:

Maximum number of people is 35

Step-by-step explanation:

With a total of $160 you have to pay for the bus and all the people. The bus cost $90 so you subtract that from the 160 because you bought (or rented) the bus. Then you have $70 left to pay for everyone's tickets. If each ticket is $2 then you can buy 35 tickets in total because 70 divided by 2 = 35.

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] Monica Geller, head chef at Allesandro's and is looking to update the commercial equipment in her kitchen and bar that will al
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Answer:

The maximum amount that should be spent on the upgrade is $38,298,000.

Step-by-step explanation:

Let the initial purchase be <em>x</em>.

The ROI = 15% of <em>x</em> = 0.15<em>x</em>

At the end of 4 years, salvage value = 10% of <em>x</em> = 0.1<em>x</em>

<em />

Current income per day = $16 × 230 = $3680

Expected income per day = $21 × 245 = $5145

Increase in income per day = $5145 - $3680 = $1465

For 4 years (assuming a year is 365 days),

Increase in income = $1465 × 365 × 4 = $2138900

Maintenance and utility cost for 4 years = 4 × $56000 = $224000

At the end of 4 years,

ROI = $2138900 + salvage value = $2138900 + 0.1<em>x</em> - $224000

0.15<em>x</em> = $1914900 + 0.1<em>x</em>

0.05<em>x</em> = $1914900

<em>x</em> = $38298000

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3 years ago
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Carlotta is making blue and orange necklaces in several lengths. For each necklace, her ratio of blue beads to orange beads is 3
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Eva is short on frosting! She works in a bakery and has 12 cakes to frost, but she is short 418 cups on the amount of frosting r
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The frosting which will be short on each of Eva's 12 cakes shared equally on each will be \frac {11}{32}

Number of cakes to frost = 12

Shortage on required frosting = 4 \frac{1}{8}

<u>Spreading the frost on each of the 12 cakes available</u> :

Divide the shortage on required frost by the number of cakes

Shortage on required frosting ÷ Number of cakes to frost

\frac{33}{8} \div 12 = \frac{33}{8} \times \frac{1}{12} = \frac{(33\times1)}{96} = \frac {11}{32}

Therefore, each frosted cake will be short of \frac{11}{32} \: cups

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