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andrew-mc [135]
3 years ago
14

Deandre rented a truck for one day. There was a base fee of

Mathematics
2 answers:
hjlf3 years ago
8 0
I am not sure but this is what I got-

217.39-14.95 to find the cost before the base fee. which is 202.44

then i did this= 202.44 / .84= 241

so the answer is 241 miles
worty [1.4K]3 years ago
3 0
He drove 238 miles in the truck. That is $217.39 minus the $14.95 base fee. That leaves $202.44. $202.44 divided by $0.84 for each mile equals 238 miles.
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Translate into an algebraic expression: If I travel d miles in h hrs downstream on a river with a current of c mph, what would m
xenn [34]

Answer:

The speed is still water is v = \frac{d}{h} - c.

Step-by-step explanation:

Dimentionally speaking, speed is distance divided by time. Since, the person is travelling downstream, absolute speed is equal to the sum of current speed and speed of the person regarding current. Both components are constant. That is:

c + v = \frac{d}{h}

Where:

c - Current speed, measured in miles per hour.

v - Speed of the person regarding current, measured in miles per hour.

d - Distance travelled downstream, measured in miles.

h - Time spent on travelling, measured in hours.

Speed in still water occurs when current speed is zero. Then, such variable is obtained after subtracting current speed on both sides of the expression. Hence:

v = \frac{d}{h} - c

The speed is still water is v = \frac{d}{h} - c.

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aleksklad [387]
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Which is larger 10cm:1mm
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Two points in the Cartesian plane are A(2.00 m, −4.00 m) and B(−3.00 m, 3.00 m). Find the distance between them and their polar
Brrunno [24]

The distance between the two points is d=8.6m

The polar coordinate of A is \left(4.47,296.57\right)

The polar coordinate of B is \left(4.24,135\right)

Explanation:

The two points are A(2,-4) and B(-3,3)

The distance between two points is given by,

d=\sqrt{(2+3)^{2}+(-4-3)^{2}}\\d=\sqrt{(5)^{2}+(-7)^{2}}\\d=\sqrt{25+49}\\d=8.6

Thus, the distance between the two points is d=8.6m

The polar coordinates of A can be written as (Distance, tan^{-1} \frac{y}{x} )

Distance = \sqrt{x^{2} +y^{2} }

Substituting A(2,-4), we get,

Distance = \sqrt{2^{2} +(-4)^{2} }=\sqrt{4+16 }=4.47

tan^{-1} \frac{y}{x} =tan^{-1} \frac{-4}{2}=-63.43

To make the angle positive, let us add 360,

\theta=360-63.43=296.57

The polar coordinate of A is \left(4.47,296.57\right)

Similarly, The polar coordinate of B can be written as (Distance, tan^{-1} \frac{y}{x} )

Distance = \sqrt{x^{2} +y^{2} }

Substituting B(-3,3), we get,

Distance = \sqrt{(3)^{2}+(3)^{2}}=4.24

tan^{-1} \frac{y}{x} =tan^{-1} \frac{3}{-3}=-45

To make the angle positive, let us add 360,

\theta=180-45=135^{\circ}

The polar coordinate of B is \left(4.24,135\right)

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3 years ago
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