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monitta
3 years ago
13

What’s the area of a circle to the nearest square foot with the radius of 7000 use 3.14 for pie

Mathematics
1 answer:
yawa3891 [41]3 years ago
7 0
Pi*r^2
3.14*7000^2
153,860,000
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I’m not understanding the answer listed on this site to the following question:
kobusy [5.1K]
Okay, I think I understand this. Our first step is to solve how long the string is after he used some of it to tie the package. I have a feeling we have to subtract 7/8 - 1/5. Find a least common multiple (in this case, it's 40) and our new fractions are 35/40 and 8/45. Subtract:

35/40 - 8/40 = 27/40.

I don't think this can be simplified down any further as they do not have any common factors. So with that in mind, let's divide 27/40 with 5/1 (5/1 is basically 5 wholes but in fraction version)

When dividing fractions, you want to use the KCF technique (my old math teacher taught me this). Keep the first fraction the same (in this case, 27/40), change the sign from multiplication to division, and flip 5/1 to get it's reciprocal, 1/5. The equation will look like this:

27/40 * 1/5 = 27/200

So each piece is about 27/200 m in length (or 0.135 m in length).

If this is wrong, please let me know, but this is what I got out of this question. I hope this helped you :)
4 0
3 years ago
If the discriminate of a quadratic equation is 28 describe the roots
katrin2010 [14]
B) two real roots is the answer because it is bigger than 0.
7 0
4 years ago
The segments represent roads in a town, measured in miles. Theo drove from the post office to the grocery store. How many miles
Ivahew [28]

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16 miles

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6 0
3 years ago
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Rachel received a $80 gift card for a coffee store. She used it in buying some coffee that cost $7.61 per pound. After buying th
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Answer:

6

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5 0
3 years ago
Read 2 more answers
WILL GIVE BEST RESPONSE
tino4ka555 [31]
We will use demonstration of recurrences<span>1) for n=1, 10= 5*1(1+1)=5*2=10, it is just
2) assume that the equation </span>10 + 30 + 60 + ... + 10n = 5n(n + 1) is true, <span>for all positive integers n>=1
</span>3) let's show that the equation<span> is also true for n+1, n>=1
</span><span>10 + 30 + 60 + ... + 10(n+1) = 5(n+1)(n + 2)
</span>let be N=n+1, N is integer because of n+1, so we have
<span>10 + 30 + 60 + ... + 10N = 5N(N+1), it is true according 2)
</span>so the equation<span> is also true for n+1, 
</span>finally, 10 + 30 + 60 + ... + 10n = 5n(n + 1) is always true for all positive integers n.
<span>
</span>
4 0
3 years ago
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