the number of elements in the union of the A sets is:5(30)−rAwhere r is the number of repeats.Likewise the number of elements in the B sets is:3n−rB
Each element in the union (in S) is repeated 10 times in A, which means if x was the real number of elements in A (not counting repeats) then 9 out of those 10 should be thrown away, or 9x. Likewise on the B side, 8x of those elements should be thrown away. so now we have:150−9x=3n−8x⟺150−x=3n⟺50−x3=n
Now, to figure out what x is, we need to use the fact that the union of a group of sets contains every member of each set. if every element in S is repeated 10 times, that means every element in the union of the A's is repeated 10 times. This means that:150 /10=15is the number of elements in the the A's without repeats counted (same for the Bs as well).So now we have:50−15 /3=n⟺n=45
Answer:
2π - 4√5
(= -2.66 to nearest hundredth).
Step-by-step explanation:
√(2π - 4√5)^2
= 2π - 4√5 (by the definition of a square root)
If you want an approximate value it is
-2.66 to the nearest hundredth
In the primitive time when the technology was not developed, human beings used to depend on nature fully for their needs, were scared of nature, followed its dictates and worshipped it. So, human beings at that time were termed as naturalized human beings. ... Thus they humanized nature with the help of technology.
Answer:
the answer is -7 3/4
Step-by-step explanation:
7.75/7.5=0.25
it is 0.25 farther from 0 than 7 1/2
Answer:
Part 8) B.F=0.5 units
Part 9) A.B=2 units
Step-by-step explanation:
we have
The diameter of circle F is 5 units
so
The radius of circle F is r.f=5/2=2.5 units
The diameter of circle G is 6 units
so
The radius of circle G is r.g=6/2=3 units
Part 8) Find B.F
we know that
B.F=G.B-F.G
we have
G.B=rg=3 units
FG=rf=2.5 units
substitute the values
B.F=3-2.5=0.5 units
Part 9) Find A.B
we know that
A.B=A.F-B.F
we have
A.F=r.f=2.5 units
B.F=0.5 units
substitute the values
A.B=2.5-0.5=2 units
