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kykrilka [37]
3 years ago
15

A chemist would like to dilute a 90-cc solution that is 5% acid to one that is 3% acid. How much water must be added to accompli

sh this task? (cc stands for cubic centimeters)
Mathematics
1 answer:
Verizon [17]3 years ago
8 0

Answer:

The amount of water must be added to this task = 60 cm^{3}

Step-by-step explanation:

Let amount of water added = x cm^{3}

Then from the given conditions

A chemist would like to dilute a 90-cc solution that is 5% acid to one that is 3% acid. So

90 (0.05) = 0.03 ( 90 + x )

4.5 = 2.7 + 0.03 x

0.03 x = 1.8

x = 60 cm^{3}

Therefore the amount of water must be added to this task = 60 cm^{3}

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Answer:

D. 20 ÷ 6 − 4

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Step-by-step explanation:

6(x + 4) = 20

6(x) + 6(4) = 20

6x + 24 = 20

     - 24  - 24

6x = -4

/6    /6

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E. 1/6(20 − 24)

1/6(-4)

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Hope this helps!

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2 years ago
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Here is your answer

Money saved on each successive day is-

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HOPE IT IS USEFUL
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Answer:

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Step-by-step explanation:

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