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kykrilka [37]
3 years ago
15

A chemist would like to dilute a 90-cc solution that is 5% acid to one that is 3% acid. How much water must be added to accompli

sh this task? (cc stands for cubic centimeters)
Mathematics
1 answer:
Verizon [17]3 years ago
8 0

Answer:

The amount of water must be added to this task = 60 cm^{3}

Step-by-step explanation:

Let amount of water added = x cm^{3}

Then from the given conditions

A chemist would like to dilute a 90-cc solution that is 5% acid to one that is 3% acid. So

90 (0.05) = 0.03 ( 90 + x )

4.5 = 2.7 + 0.03 x

0.03 x = 1.8

x = 60 cm^{3}

Therefore the amount of water must be added to this task = 60 cm^{3}

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Answer:

\large \boxed{17}

Step-by-step explanation:

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\begin{array}{cccl}6 & 16, 26, 36, 46 & 1 & \text{Only 36 is divisible by six}\\7 & 17, 27, 37, 47 & 0 & \text{None of the numbers is divisible by seven}\\8 & 18, 28, 38, 48 & 1 & \text{Only 48 is divisible by eight}\\9 & 19, 29, 39, 49 & 0 & \text{None of the numbers is divisible by nine}\\& \textbf{TOTAL =} &\mathbf{17}& \\\end{array}\\\text{$\large \boxed{\mathbf{17}}$ numbers between 10 and 50 are divisible by their units digit}

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Answer:

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Step-by-step explanation:

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