Answer:
not equivalent
Step-by-step explanation:
solve for x
4-5x=24
-5x=20
x = - 4
5x=20
x = 4
no they are not equivalent
hmmm first off let's convert the √3 +i to trigonometric form, and then use De Moivre's root theorem, bearing in mind that √3 and i or 1i are both positive, meaning we're on the I Quadrant.
![\bf (\stackrel{a}{\sqrt{3}}~,~\stackrel{b}{1i})\qquad \begin{cases} r=&\sqrt{(\sqrt{3})^2+1^2}\\ &\sqrt{3+1}\\ &2\\ \theta =&tan^{-1}\left( \frac{1}{\sqrt{3}}\right)\\\\ &tan^{-1}\left( \frac{\sqrt{3}}{3} \right)\\ &\frac{\pi }{6} \end{cases}~\hfill \implies ~\hfill 2\left[ cos\left( \frac{\pi }{6}\right) +i~sin\left( \frac{\pi }{6}\right) \right]](https://tex.z-dn.net/?f=%5Cbf%20%28%5Cstackrel%7Ba%7D%7B%5Csqrt%7B3%7D%7D~%2C~%5Cstackrel%7Bb%7D%7B1i%7D%29%5Cqquad%20%5Cbegin%7Bcases%7D%20r%3D%26%5Csqrt%7B%28%5Csqrt%7B3%7D%29%5E2%2B1%5E2%7D%5C%5C%20%26%5Csqrt%7B3%2B1%7D%5C%5C%20%262%5C%5C%20%5Ctheta%20%3D%26tan%5E%7B-1%7D%5Cleft%28%20%5Cfrac%7B1%7D%7B%5Csqrt%7B3%7D%7D%5Cright%29%5C%5C%5C%5C%20%26tan%5E%7B-1%7D%5Cleft%28%20%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B3%7D%20%5Cright%29%5C%5C%20%26%5Cfrac%7B%5Cpi%20%7D%7B6%7D%20%5Cend%7Bcases%7D~%5Chfill%20%5Cimplies%20~%5Chfill%202%5Cleft%5B%20cos%5Cleft%28%20%5Cfrac%7B%5Cpi%20%7D%7B6%7D%5Cright%29%20%2Bi~sin%5Cleft%28%20%5Cfrac%7B%5Cpi%20%7D%7B6%7D%5Cright%29%20%5Cright%5D)
![\bf ~\dotfill\\\\ \qquad \textit{power of two complex numbers} \\\\\ [\quad r[cos(\theta)+isin(\theta)]\quad ]^n\implies r^n[cos(n\cdot \theta)+isin(n\cdot \theta)] \\\\[-0.35em] ~\dotfill](https://tex.z-dn.net/?f=%5Cbf%20~%5Cdotfill%5C%5C%5C%5C%20%5Cqquad%20%5Ctextit%7Bpower%20of%20two%20complex%20numbers%7D%20%5C%5C%5C%5C%5C%20%5B%5Cquad%20r%5Bcos%28%5Ctheta%29%2Bisin%28%5Ctheta%29%5D%5Cquad%20%5D%5En%5Cimplies%20r%5En%5Bcos%28n%5Ccdot%20%5Ctheta%29%2Bisin%28n%5Ccdot%20%5Ctheta%29%5D%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill)
![\bf \left[ 2\left[ cos\left( \frac{\pi }{6}\right) +i~sin\left( \frac{\pi }{6}\right) \right] \right]^3\implies 2^3\left[ cos\left( 3\cdot \frac{\pi }{6}\right) +i~sin\left( 3\cdot \frac{\pi }{6}\right) \right] \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill 8\left[cos\left( \frac{\pi }{2} \right) +i~sin\left( \frac{\pi }{2} \right) \right]~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%5Cleft%5B%202%5Cleft%5B%20cos%5Cleft%28%20%5Cfrac%7B%5Cpi%20%7D%7B6%7D%5Cright%29%20%2Bi~sin%5Cleft%28%20%5Cfrac%7B%5Cpi%20%7D%7B6%7D%5Cright%29%20%5Cright%5D%20%5Cright%5D%5E3%5Cimplies%202%5E3%5Cleft%5B%20cos%5Cleft%28%203%5Ccdot%20%5Cfrac%7B%5Cpi%20%7D%7B6%7D%5Cright%29%20%2Bi~sin%5Cleft%28%203%5Ccdot%20%5Cfrac%7B%5Cpi%20%7D%7B6%7D%5Cright%29%20%5Cright%5D%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%208%5Cleft%5Bcos%5Cleft%28%20%5Cfrac%7B%5Cpi%20%7D%7B2%7D%20%5Cright%29%20%2Bi~sin%5Cleft%28%20%5Cfrac%7B%5Cpi%20%7D%7B2%7D%20%5Cright%29%20%5Cright%5D~%5Chfill)
Answer:
30
Step-by-step explanation:
The pattern is adding going up by 2s.
It goes like this:
+0, +2, +4, +6, +8, +10
0, 2, 6, 12, 20, 30
Hope it helps!
Answer:
![x[2x - 5][3x - 4]](https://tex.z-dn.net/?f=x%5B2x%20-%205%5D%5B3x%20-%204%5D)
Step-by-step explanation:
![6x^3 - 23x^2 + 20x \\ x[6x^2 - 23x + 20] \\ \\ [x][6x^2 - 8x] - [15x + 20] \\ \\ [x]2x[3x - 4] \: -5[3x - 4] \\ \\ x[2x - 5][3x - 4]](https://tex.z-dn.net/?f=6x%5E3%20-%2023x%5E2%20%2B%2020x%20%5C%5C%20x%5B6x%5E2%20-%2023x%20%2B%2020%5D%20%5C%5C%20%5C%5C%20%5Bx%5D%5B6x%5E2%20-%208x%5D%20-%20%5B15x%20%2B%2020%5D%20%5C%5C%20%5C%5C%20%5Bx%5D2x%5B3x%20-%204%5D%20%5C%3A%20-5%5B3x%20-%204%5D%20%5C%5C%20%5C%5C%20x%5B2x%20-%205%5D%5B3x%20-%204%5D)
I am joyous to assist you anytime.
Answer:
Kindly check explanation
0.57691
0.4719
Step-by-step explanation
A.) The distribution of sample means must follow a normal distribution ;
Mean = 64 ; Standard deviation = 17 ;
Standard Error = s/sqrt(n) = 17 / sqrt(20) = 3.8013155
N(64 ~ 17)
Given that:
mean (m) = 64
Sample size (n) = 20
Standard deviation (s) = 17
Find
P(x < 67.3)
Z = (x - m) / s
Zscore = (67.3 - 64) / 17
Zscore = 0.1941176
P(Z < 0.194) = 0.57691 (Z probability calculator)
(c) Find P(x > 65.2).
Zscore = (65.2 - 64) / 17
Zscore = 0.0705882
P(Z > 0.0705) = 0.4719 (Z probability calculator)
