Answer:
120
Step-by-step explanation:
trough dependent sarcasm
The perimeter and area of a rectangle are (5,6) and (6,5).
The perimeter method for a rectangle states that P = (L + W) × 2, where P represents perimeter, L represents length, and W represents width. when you are given the size of a square form, you may simply plug within the values of L and W into the formula that allows you to clear up for the fringe.
A perimeter is a closed course that encompasses, surrounds, or outlines either a two-dimensional shape or a one-dimensional period. The perimeter of a circle or an ellipse is known as its circumference. Calculating the perimeter has several practical programs.
The perimeter P of a rectangle is given by means of the method, P=2l+2w, in which l is the period and w is the width of the rectangle. The place A of a rectangle is given with the aid of the components, A=lw, wherein l is the length and w is the width.
The perimeter of the rectangle:
P=2l+2w=22
divide 2 into both sides
l+w=11 -------------> (1)
w=11-l
Area of the rectangle:
l*w=30
l(11-l)=30
11l-l^2-30=0
l^2-11l+30=0
By factor method,
(l-5)(l-6)=0
l=5,6.
Substitute this value in w,
l=5 implies w=6
l=6 implies w=5
There we have two solutions.
The length and breadth of the rectangle is
(5,6) and (6,5).
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Answer:
m=2
Step-by-step explanation:
(x1,y1)=(−7,−6)
(x2,y2)=(−3,2)
m=
y2−y1 / x2−x1
= 2−−6 / −3−−7
= 8/4
m=2
Can you give me Brianliest please
Answer:
2 non real solutions.
Step-by-step explanation:
We need to use discriminant,
for ax²+bx+c=0
The discriminat is b²-4ac
If the discriminant is,
→ less than 0, then 0 real solutions
→ equal to 0, then 1 real solutions
→ more than 0, then 2 real solutions
Given that,
7x²−4x+3=0
a=7, b=-4, and c=3
→ (-4)²-4(7)(3)
→ 16-84
→ -68
You can see this is less than 0, then non real solutions. [2 nonreal solutions]
Answer:
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