Answer:
Hypotenuse ^2= long leg^2 + short leg^2.
Step-by-step explanation:
THIS EQUATION ONLY WORKS FOR A RIGHT TRIANGLE
Answer:
c
Step-by-step explanation:
Answer:
Step-by-step explanation:
![(x+1-i)(x+1+i)\\\\=(x+1)^2 -i^2~~~~~~~~~~~~~;[a^2 -b^2 = (a+b)(a-b)]\\\\=x^2 +2x +1 -(-1)\\\\=x^2 +2x +1+1\\\\=x^2 +2x +2](https://tex.z-dn.net/?f=%28x%2B1-i%29%28x%2B1%2Bi%29%5C%5C%5C%5C%3D%28x%2B1%29%5E2%20-i%5E2~~~~~~~~~~~~~%3B%5Ba%5E2%20-b%5E2%20%3D%20%28a%2Bb%29%28a-b%29%5D%5C%5C%5C%5C%3Dx%5E2%20%2B2x%20%2B1%20-%28-1%29%5C%5C%5C%5C%3Dx%5E2%20%2B2x%20%2B1%2B1%5C%5C%5C%5C%3Dx%5E2%20%2B2x%20%2B2)
Answer:
c = 69 and h = 51
Step-by-step explanation:
You will need two different equations here
use variable c as coffee and variable h as hot chocolate
c + h = 120
1.80c + 3.15h = 284.40
By moving variables, you can alter the first equation
h = 120 - c
Now insert this into the second equation
1.80c + 3.15(120 - c) = 284.40
Multiply
1.80c + 378 - 3.15c = 284.40
Subtract the c
-1.35c + 378 = 284.40
Subtract 378 from both sides
-1.35c = -93.6
Divide both sides by -1.35
c = 69
Then plug into the first equation
69 + h = 120
Subtract 69
h = 51
