Answer:
The numbers are -14,-13 and -12
Step-by-step explanation:
<u><em>The correct question is </em></u>
Find three consecutive integers such that the sum of the first, twice the second and three times the third is -76. What is the number?
Let
x ----> the first consecutive integer
x+1 ---> the second consecutive integer
x+2 ---> the third consecutive integer
we have that

solve for x
apply distributive property

Combine like terms

subtract 8 both sides


Divide by 6 both sides

so


therefore
The numbers are -14,-13 and -12
#1 is a right isosceles
#2 I think is equilateral
#3 it is obtuse
#4 I think its scalene
I hope I helped :)
Answer:
The mean is 21.62 which is approximately 22
Step-by-step explanation:
mean= 15+20+10+12+20+16+80+18/8=21.62 because
mean= sum of all numbers/numbers mentioned
Even integer: 2 x a, where a is a natural number without 0;
Odd integer : 2 x b + 1 , where b is a natural number;
So, 2 x a + 2 x b+ 1 = 2 x ( a + b ) + 1, which is an odd integer.
Answer:
2•2²×100+5.
Step-by-step explanation: