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Lesechka [4]
4 years ago
8

Find the values of x and y.

Mathematics
1 answer:
Semmy [17]4 years ago
4 0
Check the picture below.

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The slope of y= 1/2x-7 is___
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Because 300 is the only liked denominator between the two

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If you "ate a ton" of Quater Pounders and they weighed exactly a quarter pound each, how many would you have eaten? ( 1 ton= 2,0
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Use logarithmic differentiation to find dy/dx: y=((x^3)(2x+3)^1/2) / (x-2)^2
sukhopar [10]
y=\frac { { { x }^{ 3 }\left( 2x+3 \right)  }^{ \frac { 1 }{ 2 }  } }{ { \left( x-2 \right)  }^{ 2 } }

\\ \\ { \left( x-2 \right)  }^{ 2 }\cdot y={ x }^{ 3 }{ \left( 2x+3 \right)  }^{ \frac { 1 }{ 2 }  }

\\ \\ \ln { \left( { \left( x-2 \right)  }^{ 2 }\cdot y \right)  } =\ln { \left( { x }^{ 3 }{ \left( 2x+3 \right)  }^{ \frac { 1 }{ 2 }  } \right)  }

\\ \\ \ln { \left( { \left( x-2 \right)  }^{ 2 } \right)  } +\ln { y } =\ln { \left( { x }^{ 3 } \right)  } +\ln { \left( { \left( 2x+3 \right)  }^{ \frac { 1 }{ 2 }  } \right)  }

\\ \\ 2\ln { \left( x-2 \right)  } +\ln { y } =3\ln { x } +\frac { 1 }{ 2 } \ln { \left( 2x+3 \right)  }

\\ \\ \ln { y } =3\ln { x } -2\ln { \left( x-2 \right)  } +\frac { 1 }{ 2 } \ln { \left( 2x+3 \right)  }

\\ \\ \frac { 1 }{ y } \cdot \frac { dy }{ dx } =\frac { 3 }{ x } -\frac { 2 }{ x-2 } +\frac { 1 }{ 2x+3 }

\\ \\ y\cdot \frac { 1 }{ y } \cdot \frac { dy }{ dx } =y\left( \frac { 3 }{ x } -\frac { 2 }{ x-2 } +\frac { 1 }{ 2x+3 }  \right)

\\ \\ \frac { dy }{ dx } =\frac { { x }^{ 3 }\sqrt { 2x+3 }  }{ { \left( x-2 \right)  }^{ 2 } } \cdot \left( \frac { 3 }{ x } -\frac { 2 }{ x-2 } +\frac { 1 }{ 2x+3 }  \right)
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