0 = 0
The input is an identity: it is true for all values
Answer:
P'Q' is equal in length to PQ.
Step-by-step explanation:
Before rotation
P(-5, 3)
Q(-1, 3)
we get the length
L = √((-1-(-5))²+(3-3)²) = √((-4)²+(0)²) = 4
After rotation
P'(3, 5)
Q'(3, 1)
we get the length
L' = √((3-3)²+(1-5)²) = √((0)²+(-4)²) = 4
we can say that L = L' = 4
P'Q' is equal in length to PQ.
The perimeter of the larger polygon will have the same ratio to the perimeter of the smaller as the ratio of the corresponding sides. Therefore, the larger polygon will have a perimeter of 30(15/12) = 37.5, or 38 to the justified number of significant digits stated.
Yep they do, because if you plug in y for both equations, you get x=0. To find y, plug in 0 for either equation to get -7. (0,-7) should work for both equations since the intersection point is the point where both equations meet.