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kicyunya [14]
3 years ago
7

4x + 5 = x + 26​ need help

Mathematics
1 answer:
motikmotik3 years ago
7 0

Answer:

x = 7

Step-by-step explanation:

4x + 5 = x + 26

4x - x = 26 - 5

3x = 21

x = 21/3

x = 7

Check:

4*7 + 5 = 7 + 26

28 + 5 = 33

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Mace
vovangra [49]

Answer:

150

Step-by-step explanation:

radius is the half of one whole circle so

75 is the half to complete it add another 75

so 75+75 = 150

carry on learning

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7 0
3 years ago
Sam rides his bike at a rate of 15 miles per hour. How many feet per minute is this?
Triss [41]
Si tu prend un chien de 12k je crois que ta réponse va donner 15000
7 0
3 years ago
Topic: The Quadratic Formula
Finger [1]

Answer:

Step-by-step explanation:

The quadratic formula for a equation of form

ax²+bx + c = 0 is

x= \frac{-b +- \sqrt{b^2-4ac} }{2a}

For the first equation,

x²+3x-4=0,

we can match that up with the form

ax²+bx + c = 0

to get that

ax² =  x²

divide both sides by x²

a=1

3x = bx

divide both sides by x

3 = b

-4 = c

. We can match this up because no constant multiplied by x could equal x² and no constant multiplied by another constant could equal x, so corresponding terms must match up.

Plugging our values into the equation, we get

x= \frac{-3 +- \sqrt{3^2-4(1)(-4)} }{2(1)} \\= \frac{-3+-\sqrt{25} }{2} \\ = \frac{-3+-5}{2} \\= -8/2 or 2/2\\=  -4 or 1

as our possible solutions

Plugging our values back into the equation, x²+3x-4=0, we see that both f(-4) and f(1) are equal to 0. Therefore, this has 2 real solutions.

Next, we have

x²+3x+4=0

Matching coefficients up, we can see that a = 1, b=3, and c=4. The quadratic equation is thus

x= \frac{-3 +- \sqrt{3^2-4(1)(4)} }{2(1)}\\= \frac{-3 +- \sqrt{9-16} }{2}\\= \frac{-3 +- \sqrt{-7} }{2}\\

Because √-7 is not a real number, this has no real solutions. However,

(-3 + √-7)/2 and (-3 - √-7)/2 are both possible complex solutions, so this has two complex solutions

Finally, for

4x² + 1= 4x,

we can start by subtracting 4x from both sides to maintain the desired form, resulting in

4x²-4x+1=0

Then, a=4, b=-4, and c=1, making our equation

x=\frac{-(-4) +- \sqrt{(-4)^2-4(4)(1)} }{2(4)} \\= \frac{4+-\sqrt{16-16} }{8} \\= \frac{4+-0}{8} \\= 1/2

Plugging 1/2 into 4x²+1=4x, this works as the only solution. This equation has one real solution

7 0
3 years ago
WILL MAKE BRAINLIEST!!
kkurt [141]
I think it is -2, if that helps
4 0
3 years ago
The length of a rectangle is 5 more than twice the width. the perimeter is 130. what is the area?
vekshin1
<span>L the length     W the width 

The length of a rectangle is 5 more than twice the width</span>
L = 5+ 2W

<span>the perimeter is equal the sum of sides =130
</span>
L+L+W+W =130

by subtitution we replace L by <span>L = 5+ 2W

</span>5+ 2W+<span>5+ 2W +W+W = 130
</span>
6W= 120

w= 20              <span>L = 5+ 2W= 5+ 40=45</span>
7 0
3 years ago
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