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kykrilka [37]
3 years ago
15

I need a few help on these questions...

Mathematics
2 answers:
Sloan [31]3 years ago
6 0

Answer:

Hi, hows life going?

Step-by-step explanation:

kenny6666 [7]3 years ago
5 0
Look it up on google
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Find the domain and range of each relation. Then determine if the relation is a function. ​
Vlad [161]

Answer:

There is no fixed domain, meaning it is ongoing

The range is from -1 ≤ x ≤ 3

It is a function

Step-by-step explanation:

Domain refers to the x values. If there was a domain then there would be a dot or a point signalling that there is a fixed domain, however, there are arrows meaning that it will keep going.

The range refers to the y-values. The lowest y-value is -1 and the highest is 3.

It is a function because, when you do the vertical line test, each x-value has its own y-value.

3 0
3 years ago
X 2 +10x+22=13x, squared, plus, 10, x, plus, 22, equals, 13 1) Rewrite the equation by completing the square. Your equation shou
Masteriza [31]

Answer:

(x + 5)^2 = (5 - 3)^2

Step-by-step explanation:

Given the equation;

x^2 + 10x + 22 = 13

We have;

x^2 + 10x = 13 - 22

x^2 + 10x = -9

Adding half of 10 to both sides and completing the square as usual, we have;

(x + 5)^2 = 5^2 + (-9)

(x + 5)^2 = (5 - 3)^2

5 0
3 years ago
Read 2 more answers
Sadie's dinner bill is $18, and she leaves
Hatshy [7]

Answer:

what is the question, true or false?

Step-by-step explanation:

6 0
3 years ago
Find an explicit rule for the nth term of a geometric sequence where the second and fifth terms are -6 and 162, respectively.
Step2247 [10]
Hello,

a(2)=-6
a(3)=-6*r
a(4)=-6*r²
a(5)=-6*r^3=162
a(5)/a(2)=r^3=162/(-6)=-27==>r=-3

a(1)=-6/(-3)=2
a(2)=2*(-3)
a(3)=2*(-3)²
a(4)=2*(-3)^3
a(5)=2*(-3)^4

a(n)=2*(-3)^(n-1)




Answer
5 0
3 years ago
Read 2 more answers
Use the formula to find the area use 3.14 for pie the circle is 15 cm
alexandr402 [8]
Hey there!

A= \pi r^2

By using this formula, we plug it in.

Your correct answer would be . . .

A  ≈ \boxed{\boxed{706.86}}

Hope this helps.
~Jurgen
5 0
3 years ago
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