For a polynomial of the form ax^2+bx+c rewrite the middle term as a sum of two terms whose product is a⋅c=5⋅4=20 and whose sum is b=12.
<u>Factor 12 out of 12x.</u>
5x^2+12(x)+4
<u>Rewrite 12 as 2 plus 10</u>
5x^2+(2+10)x+4
Apply the distributive property.
5x^2+2x+10x+4
Factor out the greatest common factor from each group.
Group the first two terms and the last two terms.
(5x^2+2x)+10x+4
Factor out the greatest common factor (GCF) from each group.
x(5x+2)+2(5x+2)
Factor the polynomial by factoring out the greatest common factor, 5x+25x+2.
(5x+2)(x+2)
Answer:
(a) x = 
(b) x = 
Step-by-step explanation:
A. sum of angles in a polygon = (n - 2) 180
The polygon given is an irregular pentagon, where n = 5
So that;
sum of angles in a pentagon = (5 - 2) 180
= 3 x 180
= 
Thus,
x + 90 + 76 + 110 + 136 =
x + 412 =
x = - 412
x =
B. The polygon given is an irregular pentagon, where n = 5.
Let the supplementary angle with angle 38 be represented by y,
y + 38 = 180
y = 180 - 38
= 
y =
Let the supplementary angle with x be represented by z, so that;
z + 72 + 120 + 100 + 142 =
z + 434 =
z = - 434
= 
z =
But, x + z = 
Then;
x + =
x = -
=
x =
Let's say "n" is a natural number. {1,2,3,4,..} To ensure we have an even number we will multiply "n" by 2. Two times any number will make an even number.
consecutive even numbers are like; 2, 4, 6, 8, 10 .. etc. Add +2 to the previous number to get the next consecutive.
1st even number = 2n
2nd even number = 2n + 2
3rd even number = 2n + 4
twice the first number (2n) is 20 more then the second (2n + 2).
2(2n) = 2n + 2 + 20
4n = 2n + 22
4n - 2n = 22
2n = 22
n = 11
Now use n = 11 to find the 3 consecutive even numbers.
1st even number = 2(11) = 22
2nd even number = 2(11) + 2 = 24
3rd even number = 2(11) + 4 = 26
22, 24, 26
Answer:
12n-6
Step-by-step explanation:
hope this helps!
