Use Order Of Operations to solve 12/3x[15-6]+3
2 answers:
Hello there!
<u><em>36x+3 is the correct answer.</em></u>
<u><em>Order of operations stands for: p-parenthesis, e-exponents, m-multiply, d-divide, a-add, and s-subtracting. </em></u>
<em>First you had to divide by the numbers.</em>
And it gave us ⇒
<em>You had to subtract by parenthesis first.</em>
And it gave us ⇒
<em>Then multiply by the numbers.</em>
And it gave us ⇒
And it gave us the final answer is<u><em> </em></u><u><em>36x+3 is the final answer. </em></u>
Hope this helps! And thank you for posting your question at here on brainly, and have a great day. -Charlie
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Answer:
1.U={1,2,3,4,5}
A={2}
B={2,3}
C={4,5}
2.U={1,2,3,4}
A={1,2}
B={2,3}
C={4}
Step-by-step explanation:
We are given that and
are different sets
1.We have to construct a universe set U and non empty sets A,B and C so that above set in fact the same
Suppose U={1,2,3,4,5}
A={2}
B={2,3}
C={4,5}
{2,3,4,5}
={2}
{2,3,4,5}={2}
={2}
={2}
Hence,
2.We have to construct a universe set U and non empty sets A,B and C so that above sets are in fact different
Suppose U={1,2,3,4}
A={1,2}
B={2,3}
C={4}
={2,3,4}
={1,2}
={1,2}
={1,2}
{2,3,4}={2}
Hence,