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3 years ago

What is the formula for midpoint, perpendicular slope, and equation of a perpendicular bisector

Mathematics

1 answer:

LUCKY_DIMON [66]3 years ago

5 0

This are the formulas hope they help

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Which graph shows y=2⌈x⌉−3 ?

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Answer:

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3 years ago

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Can someone please help me to find the remainder when f(x) is divided by (x^2-4)?

yuradex [85]

Answer:

Step-by-step explanation: Given : f(x)=x

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3 years ago

N.) Evaluate the expression (xy)? + 8, when x = 2 and y = 4.

kodGreya [7K]

Answer:

Step-by-step explanation:

x=2. y=4

following bodmas

2*4=8

8+8=16

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3 years ago

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Find the value of tan(sin^-1(1/2))

suter [353]

If you know that $\sin\dfrac\pi3=\dfrac12$ , then you know right away

$\tan\left(\sin^{-1}\dfrac12\right)=\tan\dfrac\pi3=\dfrac1{\sqrt}3=\dfrac{\sqrt3}3$

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Otherwise, you can derive the same result. Let $\theta=\sin^{-1}\dfrac12$ , so that $\sin\theta=\dfrac12$ . $\sin^{-1}$ is bounded, so we know $-\dfrac\pi2\le\theta\le\dfrac\pi2$ . For these values of $\theta$ , we always have $\cos\theta\ge0$ .

So, recalling the Pythagorean theorem, we find

$\cos^2\theta+\sin^2\theta=1\implies\cos\theta=\sqrt{1-\sin^2\theta}=\sqrt{1-\left(\dfrac12\right)^2}=\dfrac{\sqrt3}2$

Then

$\tan\theta=\tan\left(\sin^{-1}\dfrac12\right)=\dfrac{\sin\theta}{\cos\theta}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}=\dfrac{\sqrt3}3$

as expected.

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3 years ago

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If y varies directly with x and y doubles then x?

arsen [322]

Answer:

Also doubles

Step-by-step explanation:

Hope this helps. Have a nice day you amazing bean child.

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