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DanielleElmas [232]
3 years ago
13

Can a triangle have more than one obtuse angle?

Mathematics
2 answers:
xxMikexx [17]3 years ago
7 0
No, a triangle cannot have more than one obtuse angle. Obtuse angles are bigger than 90 degrees but smaller than 180 degrees. Pretend we had two obtuse angles both measuring 135 degrees and an acute angle measuring 23 degrees.

135 + 135 + 23 = 293
therefore, it wouldn't be a triangle anymore... a triangle only equals up to 180 degrees. 

I hope that helps.
Marina CMI [18]3 years ago
6 0
No it can not have more than one obtuse angle.
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ANSWER ASAP<br> 4 power of 3 +2(3-2).<br> 14 <br> 16<br> 66<br> 68<br> ITS NOT 45
8_murik_8 [283]
4(3) + 2(3-2)
4(3) + 2(1)
64 + 2
the answer is 66
8 0
3 years ago
Read 2 more answers
What is the value of m?
valentinak56 [21]
Hey, Yeah the answer is 9 because
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6 0
4 years ago
Did I do this right? Please tell me if I made any mistakes
Mekhanik [1.2K]

Answer:

nope this is completely correct good job!

Step-by-step explanation:

4 0
3 years ago
Please I beg you help me
Elena L [17]

Answer:

Option D

Step-by-step explanation:

Going through the choices will help determine which option best simulates the random selection of a voter.

<u>Flip a coin three times, and assign outcomes as follows: HHH, HHT, or HTH = Nava; HTT, THH, or THT = Jensen; TTH = Moretti, TTT = Chang.</u>

Given that it is a random selection of the 4 candidates, it means the probability of choosing either one of them is equivalent. From the option, it can be found that Nava and Jensen have a higher chance of being voted than Moretti and Chang, which would not fit the criteria of being randomly selected.

<u>Roll a number cube, and assign outcomes as follows: 1 or 2 = Nava, 3 or 4 = Jensen, 5 = Moretti, 6 = Chang.</u>

Again, Nava and Jensen have a higher chance of being voted than Moretti and Chang. Therefore, this is not the correct option to simulate random selections of the 4 candidates.

<u>Roll a number cube, and assign outcomes as follows: 1, 2, or 3 = Nava, 4 = Jensen, 5 = Moretti, 6 = Chang.</u>

Nava has a higher chance of being voted, so this option does not fit the stimulation.

<u>Flip a coin twice, and assign outcomes as follows: HH = Nava, HT = Jensen, TH = Moretti, TT = Chang</u>

In this scenario, all 4 candidates have an equal chance of being voted, so this option would best simulate the random selection of a voter from the city.

Hope this helps :)

8 0
3 years ago
Solve the inequality: -2x + 5 ≥ 3x + 20 <br> A) x ≤ 15 <br> B) x ≤ 3 <br> C) x ≥ 3 <br> D) x ≤ -3
balandron [24]

Answer:

D) x \leqslant  - 3

Explanation provided above.

6 0
3 years ago
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