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4 years ago

NEED HELP PLEASE! (GIVING A LOT OF POINTS)

Mathematics

1 answer:

Pani-rosa [81]4 years ago

5 0

Try this option (the way shown is not the shortest one).

Change the design according to the local requirements.

Answer: y=3x-45

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What is the slope of the line that contains the points (-2, 7) and (2, 3)?

stealth61 [152]

Answer:

-1

Step-by-step explanation:

We can use the slope formula when given two points

m= ( y2-y1)/(x2-x1)

= ( 3-7)/(2 - -2)

= (3-7)/( 2+2)

= -4/4

= -1

6 0

3 years ago

Find the degree of the polynomial<br> 2x^4y^2+9x^2y^5-3x^4y^4

coldgirl [10]

Answer:

the polynomial has degree 8

Step-by-step explanation:

Recall that the degree of a polynomial is given by the degree of its leading term (the term with largest degree). Recall as well that the degree of a term is the maximum number of variables that appear in it.

So, let's examine each of the terms in the given polynomial, and count the number of variables they contain to find their individual degrees. then pick the one with maximum degree, and that its degree would give the actual degree of the entire polynomial.

1) term $2\,x^4\,y^2$ contains four variables "x" and two variables "y", so a total of six. Then its degree is: 6

2) term $9\,x^2\,y^5$ contains two variables "x" and five variables "y", so a total of seven. Then its degree is: 7

3) term $-3\,x^4\,y^4$ contains four variables "x" and four variables "y", so a total of eight. Then its degree is: 8

This last term is therefore the leading term of the polynomial (the term with largest degree) and the one that gives the degree to the entire polynomial.

8 0

4 years ago

Read 2 more answers

Solve x – 5 = 16 for x.

insens350 [35]

Get x all alone on its own side:
x=16+5
x=21

5 0

3 years ago

Read 2 more answers

Convert 1 cal/(m^2 * sec * °C) into BTU/(ft^2 * hr * °F)

Crazy boy [7]

Answer:

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

Step-by-step explanation:

To find : Convert $1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}$ into $\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

Solution :

We convert units one by one,

$1\text{ m}^2=10.7639\text{ ft}^2$

$1\text{ sec}=\frac{1}{3600}\text{ hour}$

$1\text{ cal}=0.003968\text{ BTU}$

Converting temperature unit,

$^\circ C\times \frac{9}{5}+32=^\circ F$

$1^\circ C\times \frac{9}{5}+32=33.8^\circ F$

So, $1^\circ C=33.8^\circ F$

Substitute all the values in the unit conversion,

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{10.7639\times \frac{1}{3600}\times 33.8}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=\frac{0.003968}{0.101061}\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

$1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

Therefore, The conversion of unit is $1\ \frac{\text{cal}}{m^2\times sec\times ^\circ C}=0.03926\frac{\text{BTU}}{ft^2\times hr\times ^\circ F}$

3 0

3 years ago

Write a rule that represents the function. <br> (1,1/2),(2,1/4),(3.1/8),(4,1/16),(5,1/32)

ratelena [41]

Answer:

Step-by-step explanation:

. cubesi, 20,64. AV 1,6,11,16... Add 5. 1, 2, 4, 8. . Multiply 2. $2,9,28,65... cubes add 1. 31,49,16 ...

5 0

3 years ago