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Anit [1.1K]
3 years ago
11

A mobile company charges a fixed rate of x cents per minute for the first 120 minutes of talk time and another rate of y cents p

er minute for each additional minute of talk time. Ethan paid $26.80 and $32.40 for 175 mins and 210 minutes of talk time on two different occasions respectively. find the amount he has to pay if he uses 140 mins of talk time.
Mathematics
1 answer:
patriot [66]3 years ago
4 0

Answer:

$21.2

Step-by-step explanation:

From the problem given, we express them as algebra so that we can easily solve;

    the total charge on a call greater than 120min is given as;

   120x + y(n - 120) = total cost of call

where n is the number of minutes which is greater than 120;

  •   Ethan paid $26.80  for 175 mins

  n = 175min here;

      120x + y(175 - 120) = 26.80

       120x + 55y = 26.80 ----- (I)

  • $32.40 for 210 minutes

      n = 210min

       120x + y(210 - 120) = 32.4

       120x + 90y = 32.4 ----- (II)

Now let us solve both equations for y and x;

      120x + 55y = 26.80 ----- (I)

     120x + 90y = 32.4 ----- (II)

subtract the two equations;

             90y - 55y = 32.4 - 26.8

                  35y = 5.6

                       y = \frac{5.6}{35}  = 0.16cents

then x;

       120x = 26.8 - 55y from equation I

       120x = 26.8 - 55(0.16)

       120x = 18

            x = \frac{18}{120}  = 0.15cents

Find the cost of 140min of talk time;

  n =140min;

      =  120(0.15) + 0.16(140 - 120)

      = 18 + 0.16(20)

      = 18 + 3.2

      = $21.2

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Step-by-step explanation:

Given : Sample size : n= 33

Critical value for significance level of \alpha:0.05 : z_{\alpha/2}= 1.96

Sample mean : \overline{x}=2.5

Standard deviation : \sigma= 0.5

We assume that this is a normal distribution.

Margin of error : E=\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}

i.e. E=\pm (1.96)\dfrac{0.5}{\sqrt{33}}=\pm0.170596102837\approx\pm0.1706

Hence, the  margin of error is \pm0.1706

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3 years ago
Suppose you have rolled a six-sided die fifty times and recorded the result of each roll.
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Using it's concept, it is found that the relative frequency  probability of rolling an even number based on this experiment is \frac{11}{25}.

A relative frequency is the <u>number of desired outcomes divided by the number of total outcomes</u>.

In this problem:

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The <u>relative frequency</u> is given by:

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A similar problem is given at brainly.com/question/20630951

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A cylinder has radius 2.5 cm and lateral area 20 pi cm^2. What is the surface area of the cylinder in terms of pi?
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This is the concept of areas of solid materials; the surface area of the cylinder whose radius is 2.5 cm and lateral area is 20 pi cm^2 will be: Surface area of cylinder is given by:
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SA=2πr^2+πrl
Area of the cyclic sides will be:
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3 years ago
A production process is known to produce a particular item in such a way that 5 percent of these are defective. If two items are
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Answer:

0.0025 = 0.25% probability that both are defective

Step-by-step explanation:

For each item, there are only two possible outcomes. Either they are defective, or they are not. Items are independent of each other. So we use the binomial probability distribution to solve this question.

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The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

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This means that p = 0.05

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This is P(X = 2) when n = 2. So

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P(X = 2) = C_{2,2}.(0.05)^{2}.(0.95)^{0} = 0.0025

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4 0
3 years ago
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