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Assoli18 [71]
3 years ago
11

Which angle measures create a triangle with three different side lengths?

Mathematics
1 answer:
Contact [7]3 years ago
4 0

The 3 angles of a triangle add up to 180 degrees. If all 3 sides are different in length then the angles are also different.

Its choice 1

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Use the following table to help answer the question below.
MariettaO [177]

Answer:

d.

They could file for Chapter 13 bankruptcy and discharge some of their debt.

Step-by-step explanation:

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3 years ago
Six times a number equals 3 times the number, increased by 12. Find the number
tino4ka555 [31]

Answer:

x=4

Step-by-step explanation:

"A number" can be rewritten as X:

6x=3x+12

1) subtract 3x on both sides:

3x=12

2) divide both sides by 3:

x=4

4 0
3 years ago
Please may someone help with c
german

Step-by-step explanation:

Distance between two villages = d

(a) \:  \frac{4}{5}  \: of \: d =  \frac{4}{5} d \\  \\ (b) \:  \frac{3}{4}  \: of \: d =  \frac{3}{4} d  \\  \\ (c) \: \frac{4}{5} d -   \frac{3}{4} d = 1.5 \\  \\  \therefore \:   \bigg(\frac{4}{5} -   \frac{3}{4} \bigg) d = 1.5 \\  \\ \therefore \:   \bigg(\frac{4 \times 4 - 3 \times 5}{5 \times 4} \bigg) d = 1.5 \\  \\ \therefore \:   \bigg(\frac{16- 15}{20} \bigg) d = 1.5 \\  \\ \therefore \:   \bigg(\frac{1}{20} \bigg) d = 1.5 \\  \\ \therefore \: d = 1.5 \times 20 \\  \\ \:  \:  \:  \:  \:  \huge \orange{ \boxed{{ \therefore \: d = 30}}}

4 0
3 years ago
A building block is in shape of a cube with each side length of 5. what is the volume?
Alexeev081 [22]
5×5×5 = 125..... cubed
4 0
3 years ago
According to government data, 20% of employed women have never been married. If 10 employed women are selected at random, what i
Ierofanga [76]

Answer:

a) P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302

b) P(X\leq 2) = P(X=0) + P(X=1) +P(X=2)

P(X=0) = (10C0) (0.2)^0 (1-0.2)^{10-0}= 0.107

P(X=1) = (10C1) (0.2)^1 (1-0.2)^{10-1}= 0.268

P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302

And replacing we got:

P(X\leq 2) = 0.107+0.268+0.302=0.678

c) For this case we want this probability:

P(X\geq 8) = P(X=8) + P(X=9) +P(X=10)

But for this case the probability of success is p =1-0.2= 0.8

We can find the individual probabilities and we got:

P(X=8) = (10C8) (0.8)^8 (1-0.8)^{10-8} =0.302

P(X=9) = (10C9) (0.8)^9 (1-0.8)^{10-9} =0.268

P(X=10) = (10C10) (0.8)^{10} (1-0.8)^{10-10} =0.107

And replacing we got:

P(X \geq 8) = 0.677

And replacing we got:

P(X\geq 8)=0.0000779

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

Let X the random variable of interest, on this case we now that:  

X \sim Bin (n=10 ,p=0.2)

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}  

Solution to the problem

Let X the random variable "number of women that have never been married" , on this case we now that the distribution of the random variable is:  

X \sim Binom(n=10, p=0.2)  

Part a

We want to find this probability:

P(X=2)

And using the probability mass function we got:

P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302

Part b

For this case we want this probability:

P(X\leq 2) = P(X=0) + P(X=1) +P(X=2)

We can find the individual probabilities and we got:

P(X=0) = (10C0) (0.2)^0 (1-0.2)^{10-0}= 0.107

P(X=1) = (10C1) (0.2)^1 (1-0.2)^{10-1}= 0.268

P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302

And replacing we got:

P(X\leq 2) = 0.107+0.268+0.302=0.678

Part c

For this case we want this probability:

P(X\geq 8) = P(X=8) + P(X=9) +P(X=10)

But for this case the probability of success is p =1-0.2= 0.8

We can find the individual probabilities and we got:

P(X=8) = (10C8) (0.8)^8 (1-0.8)^{10-8} =0.302

P(X=9) = (10C9) (0.8)^9 (1-0.8)^{10-9} =0.268

P(X=10) = (10C10) (0.8)^{10} (1-0.8)^{10-10} =0.107

And replacing we got:

P(X \geq 8) = 0.677

3 0
3 years ago
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