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Mumz [18]
3 years ago
9

The perimeter of a square field is the same as that of a rectangular field. If the length of the rectangular field is 8 km and w

idth is 5 km , calculate the area of the square field.​
Mathematics
2 answers:
rjkz [21]3 years ago
8 0

Answer:

A(s) = 42.25 km ²

Step-by-step explanation:

P(r) = 2l + 2w = 2×8km + 2×5km = 16km + 10km = 26 km

P(r) = P(s)

P(s) = 26 km = 4l => l = 26km/4 = 6.5 km

A(s) = l² = (6.5km)² = 42.25 km ²

Bess [88]3 years ago
4 0

Answer:

42.25cm^2

Step-by-step explanation:

8+5+8+5 = 26

26/4 = 6.5

6.5x6.5 = 42.25

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Step-by-step explanation:

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2 years ago
63.7+(-26) what is 63.7 plus negative 26
andrew-mc [135]

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3 years ago
Determine whether the equation defines y as a function of x.<br> x+y=9 and x^2+y^2=1 and x=y^2
Murrr4er [49]

Answer:

Function: x+y=9

Not Function: x^2+y^2=1    and     x=y^2

Step-by-step explanation:

Given

x+y=9

x^2+y^2=1

x=y^2

Required

Determine if y is a function of x

Solving x+y=9

x+y=9

Make y the subject of formula

y = 9 - x

<em>Hence; y is a function of x</em>

Solving x^2+y^2=1

x^2+y^2=1

Subtract x² from both sides

y^2=1 - x^2

Square root of both sides

y =\± \sqrt{1 - x^2}

This implies that

y =\sqrt{1 - x^2}     or     y =-\sqrt{1 - x^2}

<em>Because </em>y<em> can be any of those two expressions, it is not a function.</em>

Solving x=y^2

x=y^2

Reorder

y^2 = x

Take square roots

y = \±\sqrt{x}

This implies that

y = \sqrt{x}      or        y = -\sqrt{x}

<em>Because </em>y<em> can be any of those two expressions, it is not a function.</em>

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3 years ago
Question
Yanka [14]

Answer:

b or 150

Step-by-step explanation:

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Triangle FXY is rotated and then translated to a new location and named triangle ABC, Which of the following is true?
Zolol [24]
It is the second one bro
8 0
2 years ago
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