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vfiekz [6]
3 years ago
12

The angle of depression from an airplane to the top of an air traffic

Mathematics
1 answer:
faust18 [17]3 years ago
3 0
<h3>Answer: approximately 8600.33397283284 feet</h3>

Round this however you need to.

===========================

Work Shown:

Check out the diagram below. We have the following points

  • A = base of the tower
  • B = point on the ground directly below the airplane
  • C = top of the tower
  • D = plane's location
  • E = point used to form the angle of depression

Based on those points, we know that

  • AC = 320 = height of tower
  • BD = 7450 = height of plane
  • CE = BD - AC = 7450-320 = 7130 = difference between the two heights

Which allows us to find the distance from C to D. Focus solely on triangle EDC. Use the sine ratio to find x.

sin(angle) = opposite/hypotenuse

sin(angle EDC) = CE/CD

sin(56) = 7130/x

x*sin(56) = 7130

x = 7130/sin(56)

x = 8600.33397283284 approximately

Make sure your calculator is in degree mode.

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Step-by-step explanation:

7 0
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At an amusement park , the cost of 3 adult tickets and 4 children’s ticket is $126.50 another customer paid $120.50 for 2 adult
KonstantinChe [14]

Answer:

1 Adult ticket=$21.50 ; 1 Children ticket=$15.50

Step-by-step explanation:

3A+4C=126.50

2A+5C=120.50

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15A+20C=632.5

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Step-by-step explanation:

7 0
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Read 2 more answers
An automotive manufacturer wants to know the proportion of new car buyers who prefer foreign cars over domestic. Step 2 of 2 : S
ziro4ka [17]

Answer:

The 85% onfidence interval for the population proportion of new car buyers who prefer foreign cars over domestic cars is (0.151, 0.205).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

Sample of 421 new car buyers, 75 preferred foreign cars. So n = 421, \pi = \frac{75}{421} = 0.178

85% confidence level

So \alpha = 0.15, z is the value of Z that has a pvalue of 1 - \frac{0.15}{2} = 0.925, so Z = 1.44.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 - 1.44\sqrt{\frac{0.178*0.822}{421}} = 0.151

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.178 + 1.44\sqrt{\frac{0.178*0.822}{421}} = 0.205

The 85% onfidence interval for the population proportion of new car buyers who prefer foreign cars over domestic cars is (0.151, 0.205).

8 0
2 years ago
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