I = V/R. So the answer is 9/200 = 0.045A = 45mA which is B
Answer:
Two systems are connected by a router. Both systems and the router have transmission rates of 1,000bps. Each link has a propagation delay of 10ms. Also, it takes router 2ms in order to process the packet (e.g. decide where to forward it). Suppose the first system wants to send a 10,000 bit packet to the second system. How long will it take before receiver system receives the entire packet.
Transmission time for first Router = 10,000 bits / 1000 bps = 10 seconds
Receiving time for seond route r= 10,000 bits / 1000 bps = 10 seconds
Propagation delay = 10ms = .01 seconds x 2 for two delays = .02 seconds
First router 2ms to process = .002 seconds
Add all the times together and we get 20.022 seconds which is the same as or 20 seconds and 22 ms
Answer:
Some of the qualities of the installed memory which HWiNFO can reveal are:
- Date of manufacture
- Memory type
- Speed of memory
Explanation:
HWiNFO is an open-source systems information app/tool which Windows users can utilize as they best wish. It helps to detect information about the make-up of computers especially hardware.
If you used HWiNFO to diagnose the memory, the following information will be called up:
- the total size of the memory and its current performance settings
- the size of each module, its manufacturer, and model
- Date of manufacture
- Memory type
- Speed of memory
- supported burst lengths and module timings,
- write recovery time etc.
Cheers
Answer:
The code will be a java-script code
Explanation:
public abstract class Phone{
private String phoneNumber ;
public Phone (String thePhoneNumber) {
phoneNumber = thePhoneNumber ;
}
public String getPhoneNumber ( ) {
return phoneNumber ;
}
public String toString ( ) {
phoneNumber = "# (" + phoneNumber + ") " ;
return phoneNumber ;
}
public abstract boolean createConnection (Network status) ;
public abstract void closeConnection( ) ;
}
Specialized software. hope this helps
