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Nataly [62]
3 years ago
13

If the clock was divided into equal fractional parts every five minutes what fraction is 5 mins= hour

Mathematics
1 answer:
lesya [120]3 years ago
7 0
5 min =hour 1/12
10 min 1/6
15 min 1/4
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alekssr [168]
5/15 = 0.33 cm3 …… that is the answer I think of you can answer mine that would be great
6 0
3 years ago
Write 0.624 as a percent and as a simplified fraction.
Doss [256]
Okay to find the percent version of 0.624 you multiply by 100. 0.624×100=62.4%. Now as a fraction the last number behind the decimal is in the thousandths place so put 624 over 1000. 624/1000 simplified it would be 78/125
5 0
3 years ago
2x+3y=12 find four solutions​
Nana76 [90]

Answer:

y = 0 and x = 6

y = 2 and x = 3

y = 4 and x = 0

y = 6 and x = -3

Step-by-step explanation:

2x+3y=12 is the equation of a straight line.

There are infinite number of solutions, but here you're probably looking for solutions where x and y are whole numbers. Trial and error will find you some, although if you examine the equation closely you see that if x is a multiple of 3 and y is a multiple of 2, then they produce terms that are the LCM (least common multiple) of 2 and 3, namely 6. That's the logic in the whole number solutions.

7 0
3 years ago
On the first day a total of 40 items were sold for $356. Define the variables and write a system of equations to find the number
Alina [70]
<h3><u><em>Question:</em></u></h3>

On the first day, a total of 40 items were sold for $356. Pies cost $10 and cakes cost $8. Define the variables, write a system of equations to find the number of cakes and pies sold, and state how many pies were sold.

<h3><em><u>Answer:</u></em></h3>

The variables are defined as:

"c" represent the number of cakes sold and "p" represent the number of pies sold

The system of equations used are:

c + p = 40 and 8c + 10p = 356

18 pies and 22 cakes were sold

<h3><em><u>Solution:</u></em></h3>

Let "c" represent the number of cakes sold

Let "p" represent the number of pies sold

Cost of 1 pie = $ 10

Cost of 1 cake = $ 8

Given that total of 40 items were sold

number of cakes + number of pies = 40

c + p = 40 ------ eqn 1

<u><em>Given items were sold for $356</em></u>

number of cakes sold x Cost of 1 cake + number of pies sold x Cost of 1 cake = 356

c \times 8 + p \times 10 = 356

8c + 10p = 356  ----- eqn 2

<u><em>Let us solve eqn 1 and eqn 2</em></u>

From eqn 1,

p = 40 - c    ---- eqn 3

Substitute eqn 3 in eqn 2

8c + 10(40 - c) = 356

8c + 400 - 10c = 356

-2c = - 44

c = 22

<em>Substitute c = 22 in eqn 3</em>

p = 40 - c

p = 40 - 22

p = 18

Thus 18 pies and 22 cakes were sold

3 0
4 years ago
The student council orders 12 sandwhiches for the school dance. each sandwich is 6 feet long cut into sections that are 4 inches
Setler [38]

The school council will have 216 small sandwiches.

Step-by-step explanation:

Sandwiches ordered = 12

Length of one sandwich = 6 feet

1 foot = 12 inch

6 feet = 12*6 = 72 inches

Length of one sandwich in inches = 72 inches

As one small sandwich is 4 inches,

Number of small sandwiches in one sandwich = \frac{72}{4}=18

One sandwich = 18 small sandwiches

12 sandwiches = 18*12 = 216 small sandwiches

The school council will have 216 small sandwiches.

Keywords: multiplication, division

Learn more about multiplication at:

  • brainly.com/question/10710410
  • brainly.com/question/10717746

#LearnwithBrainly

3 0
3 years ago
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