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hram777 [196]
3 years ago
14

I am so confused this doesn't make any sense

Mathematics
1 answer:
Ann [662]3 years ago
5 0

Answer:

1 3/4

Step-by-step explanation:

The length shown is the diameter.

The radius is half of the diameter.

so 3 1/2 divided by 2

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What value of b will cause the system to have an infinite number of solutions?
irga5000 [103]

b must be equal to -6  for infinitely many solutions for system of equations y = 6x + b and -3 x+\frac{1}{2} y=-3

<u>Solution: </u>

Need to calculate value of b so that given system of equations have an infinite number of solutions

\begin{array}{l}{y=6 x+b} \\\\ {-3 x+\frac{1}{2} y=-3}\end{array}

Let us bring the equations in same form for sake of simplicity in comparison

\begin{array}{l}{y=6 x+b} \\\\ {\Rightarrow-6 x+y-b=0 \Rightarrow (1)} \\\\ {\Rightarrow-3 x+\frac{1}{2} y=-3} \\\\ {\Rightarrow -6 x+y=-6} \\\\ {\Rightarrow -6 x+y+6=0 \Rightarrow(2)}\end{array}

Now we have two equations  

\begin{array}{l}{-6 x+y-b=0\Rightarrow(1)} \\\\ {-6 x+y+6=0\Rightarrow(2)}\end{array}

Let us first see what is requirement for system of equations have an infinite number of solutions

If  a_{1} x+b_{1} y+c_{1}=0 and a_{2} x+b_{2} y+c_{2}=0 are two equation  

\Rightarrow \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}} then the given system of equation has no infinitely many solutions.

In our case,

\begin{array}{l}{a_{1}=-6, \mathrm{b}_{1}=1 \text { and } c_{1}=-\mathrm{b}} \\\\ {a_{2}=-6, \mathrm{b}_{2}=1 \text { and } c_{2}=6} \\\\ {\frac{a_{1}}{a_{2}}=\frac{-6}{-6}=1} \\\\ {\frac{b_{1}}{b_{2}}=\frac{1}{1}=1} \\\\ {\frac{c_{1}}{c_{2}}=\frac{-b}{6}}\end{array}

 As for infinitely many solutions \frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}

\begin{array}{l}{\Rightarrow 1=1=\frac{-b}{6}} \\\\ {\Rightarrow6=-b} \\\\ {\Rightarrow b=-6}\end{array}

Hence b must be equal to -6 for infinitely many solutions for system of equations y = 6x + b and  -3 x+\frac{1}{2} y=-3

8 0
3 years ago
Samantha has a AA battery that is 51mm long. About how many centimeters long is it
Butoxors [25]

Answer:

5.1 cm

. . . . . .

All we have to do is convert our 51mm to centimeters.

We divide the length value by 10 to get our centimeters.

51 divided by 10 = 5.1

All we have to do is move our "invisible decimal"

In my way, every whole number has an invisible decimal at it's end.

For ex: '60.'

We can get into exponents. 10 is 10¹, any exponent is the number of zeros at the end of a number may have. Ex: '10² = 100'

We can move our decimal to the left since we are dividing. The amount of exponent numbers are the amount you move it, multiplying and dividing are different things with that.

Let's get back on topic.

Moving our decimal to the left with dividing is 5.1 since 10¹ has a "1" as it's exponent, making us move it "1" to the left.

Multiplying is going the right way.

I hope this helps.

5 0
3 years ago
Another 3rd grade question:
liraira [26]
To find the perimeter you would need to add 35+35+65+65=200. If the perimeter is 200, and he circles around it 4 times, 200*4=800, which is the answer. 
 Answer: The total amount of yards that Chris dribbles the ball is 800 yards.
7 0
3 years ago
Hurry!! Answer it please:))
Ksivusya [100]

Answer:

Option C.

Domain:

{3, 0, 2, 4}

Step-by-step explanation:

The domain is the set of all the values of x.

5 0
3 years ago
Read 2 more answers
NEED HELP FAST 100 POINTS AND BRAINLIEST
Shtirlitz [24]

Answer:

1)The mass of water increases.

2) Freezing point of water decreases.

3) buoyancy of objects in the water increases.

Step-by-step explanation:

Salinity in the oceanic water is attributed by the water coming from other sources like rivers carrying rocks and soil containing salt. Salinity decreases the temperature of water, making it cold and more denser. The cold water settles at the bottom of the ocean. It flows across the oceanic basins as slow currents. The objects being less in density flows over the surface of water. Hence,buoyancy of objects in water increases.

⭐ Answered by Kakashi ʕ •㉨• ʔ⭐

⭐ Brainliest would be appreciated!⭐

⭐ If you have questions, leave a comment, I'm happy to help! ⭐

7 0
3 years ago
Read 2 more answers
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