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RSB [31]
3 years ago
12

Identify each graph below as being representative of a geometric sequence, an arithmetic sequence or neither.

Mathematics
1 answer:
valina [46]3 years ago
8 0

First one arithmetic.

Second one neither.

Third one geometric.

Fourth one geometric.

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Solve the system of equations by graphing. x+y=-9 4x+y=-19
shutvik [7]

For this case we have the following system of equations:

x + y = -9\\4x + y = -19

We multiply the first equation by -4:

-4x-4y = 36

We have the following equivalent system of equations:

-4x-4y = 36\\4x + y = -19

We add the equations:

-4x + 4x-4y + y = 36-19\\-3y = 17\\y = - \frac {17} {3}

We find the value of the variable "x":

x = -9-yx = -9 - (- \frac {17} {3})\\x = -9 + \frac {17} {3}\\x = \frac {-27 + 17} {3}\\x = - \frac {10} {3}

Thus, the solution of the system is:

(x, y): (- \frac {10} {3}, - \frac {17} {3})

See the graphic in the attached image

ANswer:

(x, y): (- \frac {10} {3}, - \frac {17} {3})

See the graphic in the attached image

4 0
4 years ago
Help me with this question please
azamat

Answer:

It would be 3.

Step-by-step explanation:

In order to get 3, notice how 4 became 2 for the small triangle. Well, in this case, 4/2=2. So, do 6/2=3.

7 0
3 years ago
A stack of 10 different cards are shuffled and spread out face down. If 3 cards are turned face up, how many different 3-card co
Advocard [28]

Answer:

<h3>120 different ways</h3>

Step-by-step explanation:

Using the combination formula as shown;

nCr = n!/(n-r)!r!

If a stack of 10 different cards are shuffled and spread out face down. If 3 cards are turned face up, the number of different ways 3cards combinations are possible is expressed as;

10C3 = 10!/(10-3)!3!

10C3 = 10!/(7)!3!

10C3 = 10*9*8*7!/7!*3*2

10C3 = 10*9*8/3*2

10C3 = 720/6

10C3 = 120 different ways

Hence there are 120 different card combinations

5 0
3 years ago
A number p increased by 22
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the answer is ~

p + 22

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Zepler [3.9K]

Answer:

3

Step-by-step explanation:

5 0
3 years ago
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