Wonderful! You gave us everything we could ever possibly want
to know, except the QUESTION. Fortunately, here at Brainly, we
have five Hogwarts drop-outs who work weekends for us as our
Department of Clairvoyance. When people post an intriguing
question but leave out some important part of it, our D of C can
usually fill in the missing part for us ... especially on weekends.
The question you left out is:
What is the next time that a red bus and a blue bus
will both leave the stadium together, simultaneously
and also both at the same time ?
Since red buses leave every 6 minutes starting at 4:00, and
blue buses leave every 8 minutes starting at 4:00, they both
leave simultaneously and also at the same time at minutes
after 4:00 that are common multiples of 6 and 8.
The least common multiple of 6 and 8 is 24 . After that,
every multiple of 24 is another common multiple of 6 and 8.
24 minutes is 4 red buses and 3 blue buses ... exactly !
A red bus and a blue bus will leave the stadium together at 4:24 .
After that, it will happen again at 24-minute intervals ... at 4:48,
5:12, 5:36, 6:00, . . . etc.
Answer:
A) 8+2.50x=28
B) 8 rides
C) Jada can go on 8 rides before she has spent all of her money
Step-by-step explanation:
subtract the $8 fee from 28 and get 20, then divide 20 by how much each ride costs (2.50) and get 8 :)
I got -6/25 Sorry I can't really explain this try web2.0calc.com it helps alot with math.
