Answer:
yes the required equation is consistent
Answer:
yes
Step-by-step explanation:
heres why
Step 1: Add 5 to both sides.
7y−5+5=9+5
7y=14
then ima divide 14 by 7 which equals 2
14/7y =2
so its true
Answer:
x−3=x−3
Step-by-step explanation:
Evaluate (2x−1)−7, then set it equal to 2.
Subtract 7 from −1 = 2x−8
Solve 2x−8=2.
Move all terms not containing x to the right side of the equation.
Add 8 to both sides of the equation=2x=2+8
Add 2 and 8=2x=10
Divide each term by 2 and simplify.
Divide each term in 2x=10 by 2=2x/2=10/2
Cancel the common factor of 2
Cancel the common factor=10/2
Divide x by 1=x=10/2
Divide 10 by 2=x=5
Remove parentheses=x−3
List all of the solutions.
5=
(2x−1)−7=2=x=5
x−3=x−3
There are many possible solutions. As long as it’s a number greater than 4 it’s acceptable.
Examples:
5,6,7,8,9,10,11,12,13,14,15,16,1000,1030,1937
:)
Answer:
1st One goes to the third one
2nd one goes to the 1st one
3rd one goes to the 4th one
and the 4th one goes to the 2nd one
