(4s+3)(4s–3) i really neeed help
1 answer:
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Slope = (y2 - y1)/(x2 - x1) = (1 - 3)/(-2 - (-5)) = -2/(-2 + 5) = -2/3
For perpendicular lines, m2 = -1/m1 = -1/(3/8) = -8/3
A line passing through point (-4, 0) and parallel to the y-axis is x = -4
radius = diameter/2 = 10/2 = 5
center of circle = midpoint of diameter = ((-3 + 5)/2, (1 + 7)/2) = (2/2, 8/2) = (1, 4)
Required equation is (x - 1)^2 + (y - 4)^2 = 5^2
(x - 1)^2 + (y - 4)^2 = 25
For perpendicular lines, m2 = -1/m1 = -1/(3/8) = -8/3
A line passing through point (-4, 0) and parallel to the y-axis is x = -4
radius = diameter/2 = 10/2 = 5
center of circle = midpoint of diameter = ((-3 + 5)/2, (1 + 7)/2) = (2/2, 8/2) = (1, 4)
Required equation is (x - 1)^2 + (y - 4)^2 = 5^2
(x - 1)^2 + (y - 4)^2 = 25
Answer:
if I read your screen correctly
40
Step-by-step explanation:
divide the larger one (Sr) by smaller one (F)
the coefficient = 2/5
the exponent = -7-(-8)
can you get the answer from there, don't forget to simplify
Answer:
The original deposited amount in the bank is $3500.
Step-by-step explanation:
Here. Let us assume the principal amount deposited in bank = $P
The rate of interest = 8%
Total Amount in the bank after time period = $4340
Time Period = 3 yrs
Now, SIMPLE INTEREST
⇒ SI =
or Interest = 0.24 P
Now, AMOUNT = PRINCIPAL + INTEREST
⇒$4340 = P + 0.24 P
or, 4340 = 1.24 P
⇒ P = 1340 / 1.24 = 3500
Hence, the deposited amount in the bank for the duration of 3 years and interest rate 8% is $3500