AVERAGE between 90 and 100%
means not including 90 and 100% but not including 90 or 100%
average=(sum of values in set)/(how many values in the set)
so
4 exams, so there are 4 values
average=(sum)/4
the sum is the known+unknwon
sum=76+99+86+x
so
90<span><</span>average and average <span><</span>100
or
90<span><</span>average<span><</span>100
lets say average=a
a=sum/number
a=(76+99+86+x)/4
90<(76+99+86+x)/4<100
90<(76+99+86+x)/4 and (76+99+86+x)/4<100
solve each for x and find intersection
90<span><</span>(76+99+86+x)/4
times 4 both sides
360<span><</span>261+x
minus 261 both sides
99<span><</span>x
(76+99+86+x)/4<u><</u>100
times 4 both sides
261+x<u><</u>400
minus 261 both sides
x<u><</u>139
so
99<u><</u>x<u><</u>139
since max score is 100
99<u><</u>x<u><</u>100
interval notaion is
[99,100]
answer is 2nd one
Answer:
$90
Step-by-step explanation:
Given data
Price= $900
Rate= 25%
Time= 8 years
Let us apply the compounding formula
A= P(1-r)^t >>>>note that the negative sign is because of the depreciation
substitute
A= 900(1-0.25)^8
A= 900(0.75)^8
A= 900*0.100
A= $90
Hence the value of the car after 8 years will be $90
12 will fit in the box for number 1
-5d+(-6)u-3= -5*2-6*7-3= -10 - 42-3= -55