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2 years ago

8x+3-2(6+3x) when x= -6

Mathematics

1 answer:

Tatiana [17]2 years ago

3 0

8x + 3 - 2(6 + 3x)
8(-6) + 3 - 2(6 + 3(-6))
-48 + 3 - 2(6 - 18)
-48 + 3 - 2(-12)
-45 + 24
-21

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Find the factor of the number 1.30

Kazeer [188]

Answer:

1,2,3,5,6,10,15,30

Step-by-step explanation:

Factors of 30 are the following:-

1x30=30

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2 years ago

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Hoochie [10]

Answer:

It's 65

Step-by-step explanation:

The reason is because the whole thing needs to be 180 right.

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3 years ago

The outside temperature is -3°F and falling at a rate of 2 degrees per hour. What will the temperature be in 5 hours?

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3 years ago

Find the equation of a sphere if one of its diameters has endpoints: (-9, -12, -6) and (11, 8, 14).

baherus [9]

Answer:

Hence, the equation of a sphere with one of its diameters with endpoints (-9, -12, -6) and (11, 8, 14) is $(x-1)^{2}+(y+2)^{2}+(z-4)^{2} = 30$ .

Step-by-step explanation:

There are two kew parameters for a sphere: Center ( $h$ , $k$ , $s$ ) and Radius ( $r$ ). The radius is the midpoint of the line segment between endpoints. That is:

$C(x,y,z) = \left(\frac{-9+11}{2},\frac{-12+8}{2},\frac{-6+14}{2} \right)$

$C(x,y,z) = (1,-2,4)$

The radius can be found by halving the length of diameter, which can be determined by knowning location of endpoints and using Pythagorean Theorem:

$r = \frac{1}{2}\cdot \sqrt{(-9-11)^{2}+(-12-8)^{2}+(-6-14)^{2}}$

$r = 10\sqrt{3}$

The general formula of a sphere centered at (h, k, s) and with a radius r is:

$(x-h)^{2}+(y-k)^{2}+(z-s)^{2} = r^{2}$

Hence, the equation of a sphere with one of its diameters with endpoints (-9, -12, -6) and (11, 8, 14) is $(x-1)^{2}+(y+2)^{2}+(z-4)^{2} = 30$ .

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3 years ago