<span>6b^3 (2a+7b)
</span>
<span><span>(<span>6b^3</span>)</span><span>(<span>2a+7b</span><span>)
</span></span></span>
<span><span><span>=(<span>6b^3</span>)</span><span>(2a)</span></span>+<span><span>(<span>6b^3</span>)</span><span>(7b)
</span></span></span>
<span><span>=12ab^3</span>+<span>42<span>b^4]
Answer: </span></span></span>
<span><span><span>12a</span><span>b^3</span></span>+<span>42<span>b^4</span></span></span>
Answer:
Explanation:
The table that shows the pattern for this question is:
Time (year) Population
0 40
1 62
2 96
3 149
4 231
A growing exponentially pattern may be modeled by a function of the form P(x) = P₀(r)ˣ.
Where P₀ represents the initial population (year = 0), r represents the multiplicative growing rate, and P(x0 represents the population at the year x.
Thus you must find both P₀ and r.
<u>1) P₀ </u>
Using the first term of the sequence (0, 40) you get:
P(0) = 40 = P₀ (r)⁰ = P₀ (1) = P₀
Then, P₀ = 40
<u> 2) r</u>
Take two consecutive terms of the sequence:
- P(1) / P(0) = 40r / 40 = 62/40
You can verify that, for any other two consecutive terms you get the same result: 96/62 ≈ 149/96 ≈ 231/149 ≈ 1.55
<u>3) Model</u>
Thus, your model is P(x) = 40(1.55)ˣ
<u> 4) Population of moose after 12 years</u>
- P(12) = 40 (1.55)¹² ≈ 7,692.019 ≈ 7,692, which is round to the nearest whole number.
Simplify by combining the real and imaginary parts of each expression.
1
,
−
96
Answer:
Marneisha with 9.52 pages.
Step-by-step explanation:
Zev: 56×0.15 = 8.4
Kelly: 64×0.12 = 7.68
Marneisha: 68×0.14 - 9.52
Aleisha: 72×0.10 = 7.2
To calculate h evaluate inside the square root before taking the square root
h = √(7² - 3.5²) = √(49 - 12.25) = √36.75 = 6.06 ( to 2 dec. places)
