Answer: 142 and 286
==========================================
Explanation:
If we multiply a given term by 2, then add 2, we get
7*2+2 = 14+2 = 16
16*2+2 = 32+2 = 34
34*2+2 = 68+2 = 70
So the rule seems to be "multiply by 2, then add 2"
If that rule holds up, then the next two terms are
70*2+2 = 140+2 = 142
142*2+2 = 284+2 = 286
The order of the start of the proof seems fine; we're to choose the next steps I guess.
segment UV is parallel to segment WZ Given
Points S, Q, R, and T all lie on the same line. Given
m∠SQT = 180° Definition of a Straight Angle
m∠SQV + m∠VQT = m∠SQT Angle Addition Postulate
m∠SQV + m∠VQT = 180° Substitution Property of Equality
That's all valid up to here. It seems to me sort of the hard way to get to linear supplements but here we are.
ZRS is mentioned in the rest of the lines; let's find the one that comes first.
III m∠VQT + m∠ZRS = 180° Same-Side Interior Angles Theorem
Now we have two things equal to 180 degrees, so they're equal to each other.
II m∠SQV + m∠VQT = m∠VQT + m∠ZRS Substitution Property of Equality
Now comes
I m∠SQV + m∠VQT − m∠VQT = m∠VQT + m∠ZRS − m∠VQT
m∠SQV = m∠ZRS Subtraction Property of Equality
And we conclude,
∠SQV ≅ ∠ZRS Definition of Congruency
<span>✦ Find the cosine function.
</span><span>✦ CosX = 4.2 / 5 - 0.85
</span><span>✦ Find the inverse cosine function.
</span><span>✦ Accros0.84 = X*
</span><span>✦ = 32.86
</span>
The answer is 32.86 degrees.
<span>Hope that helps! ★ <span>If you have further questions about this question or need more help, feel free to comment below or leave me a PM. -UnicornFudge aka Nadia </span></span>
Answer:
<em>0</em> is the probability that a randomly selected student plays both a stringed and a brass instrument.
Step-by-step explanation:
Given that:
Number of students who play stringed instruments, N(A) = 15
Number of students who play brass instruments, N(B) = 20
Number of students who play neither, N()' = 5
<u>To find:</u>
The probability that a randomly selected students plays both = ?
<u>Solution:</u>
Total Number of students = N(A)+N(B)+N()' =15 + 20 + 5 = 40
(As there is no student common in both the instruments we can simply add the three values to find the total number of students)
As per the venn diagram, no student plays both the instruments i.e.
Formula for probability of an event E can be observed as:
So, <em>0</em> is the probability that a randomly selected student plays both a stringed and a brass instrument.