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Andreas93 [3]
2 years ago
15

Total piston displacement is given by the following formula: TT P.D.ED?LN 4 Where P.D. = piston displacement, in cubic inches D

= diameter of bore of cylinder L = length of stroke, in inches N = number of cycles Find the diameter if P.D. = 400 cu in., L = 4.5 in., N = 6 in. to 2 Find the diameter: decimal places Do NOT put in units​

Mathematics
1 answer:
Ede4ka [16]2 years ago
7 0

Answer: ≈ 1696460.03

Step-by-step explanation:

Formula:

P.D.=(\frac{\pi }{4})D^2LN ⇒ \left(\frac{\pi }{4}\right)400^2\cdot 4.5\cdot 6

Steps:

1. calculate pi and inset into equation

=0.785398(400^2)(4.5)(6)

2. calculate exponents

=(0.785398)(160000)(4.5)(6)

3 . multiply the rest

=(125663.706144)(4.5)(6)

=(565486.677646)(6)

4. divide by 2 to get the diameter

=\frac{3392920.065877}{2}

5. round to the nearest hundredth (2 decimal points)

= 1696460.032938 ≈ 1696460.03

Hope this helped!

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Vaselesa [24]

Answer:

4:1 (I think)

Step-by-step explanation:

Let's write some equations first:

For both prices increasing by 20:

\frac{x+20}{y+20} =\frac{5}{2}

then we can use cross multiplication

2x+40=5y+100

For both prices decreasing by 5:

\frac{x-5}{y-5} =\frac{5}{1}

same here:

5y-25=x-5

Using substitution for 5y, we get: 5y=x+20

2x+40=5y+100

2x+40=x+20+100

x=80

plugging this in to the second equation:

5y-25=x-5

5y-25=80-5

5y-25=75

5y=100

y=20

therefore we get x:y=80:20

4:1

4 0
3 years ago
A farmer has a collapsable grain bag which can expand both vertically and horizontally as he needs it to. He wants to find a fun
bija089 [108]

Answer:

3x^{3}+15x^{2}+x+5

Step-by-step explanation:

We are told that the area of the bag can be represented by the function f(x)=3x^{2} +1 and as the bag is raised up its height can be represented by the function g(x)=x +5.

Since we know that we can find volume of cuboid by multiplying base area to its height. We are given area and height of bag as functions. Now we will find volume of the bag by multiplying these functions.  

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\text{Volume of collapsible bag}=(3x^{2}+1)*(x +5)

After using distributive property we will get,

\text{Volume of collapsible bag}=3x^{2}(x+5)+1(x+5)

\text{Volume of collapsible bag}=3x^{3}+15x^{2}+x+5

Therefore, the collapsible bag can hold 3x^{3}+15x^{2}+x+5 grain.

6 0
3 years ago
Can anyone explain how to expand and simplify 3(2a+5) +5 (a-2)
Step2247 [10]
Take the first bracket and it's multiplication, 3(2a+5)
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3*2a = 6a
3*5 = 15
Then multiply out the second bracket, 5(a-2)
5*a = 5a
5*-2 = -10
So now you have 6a + 15 + 5a - 10
Simplify it by collecting like terms, and you have:
11a + 5
And that's the answer, hope I helped!
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