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Olin [163]
3 years ago
11

Find the selling price of a $270 bicycle with a 24% markup

Mathematics
1 answer:
Burka [1]3 years ago
7 0
$270 with a markup of 24% is $334.80
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What is lim x → 9+ ( x - 9/| 9 - x | )
SIZIF [17.4K]

Answer:

The answer is nonexistent

Step-by-step explanation:

6 0
3 years ago
Pls help I really need to pass this if like for 4th quarter where I m pls help me
Tom [10]

Answer:

✨Both will be the same✨

✨Step-by-step explanation:✨

there is 1 in each section 61 and 38

HOPE THAT HELPS

3 0
3 years ago
Determine the end behavior of P(x)=3x
ELEN [110]

Answer:

As x ⇒-∞, P(x) ⇒ -∞

As x ⇒ ∞, P(x) ⇒ ∞

Step-by-step explanation:

To find left hand end behavior, plug in negative infinity into the function and evaluate...

P(x) = 3(-∞) = -3(∞) = -∞

  The 'y' values of the function decrease towards negative infinity as the 'x' values approach negative infinity

P(x) = 3(∞) = ∞

  The 'y' values of the function increase towards positive infinity as the 'x' values approach positive infinity

6 0
3 years ago
Which of these strategies would eliminate a variable in the system of equations?
melomori [17]
5x -2y = 2 is the answer
8 0
2 years ago
Evaluate the expression
larisa86 [58]

Answer:

12-[20-2(6^2\div3\times2^2)]=88

Step-by-step explanation:

So we have the expression:

12-[20-2(6^2\div3\times2^2)]

Recall the order of operations or PEMDAS:

P: Operations within parentheses must be done first. On a side note, do parentheses before brackets.

E: Within the parentheses, if exponents are present, do them before all other operations.

M/D: Multiplication and division next, whichever comes first.

A/S: Addition and subtraction next, whichever comes first.

(Note: This is how the order of operations is traditionally taught and how it was to me. If this is different for you, I do apologize. However, the answer should be the same.)

Thus, we should do the operations inside the parentheses first. Therefore:

12-[20-2(6^2\div3\times2^2)]

The parentheses is:

(6^2\div3\times2^2)

Square the 6 and the 4:

(36\div3\times4)

Do the operations from left to right. 36 divided by 3 is 12. 12 times 4 is 48:

(36\div3\times4)\\=(12\times4)\\=48

Therefore, the original equation is now:

12-[20-2(6^2\div3\times2^2)]\\=12- [20-2(48)]

Multiply with the brackets:

=12-[20-96]

Subtract with the brackets:

=12-[-76]

Two negatives make a positive. Add:

=12+76=88

Therefore:

12-[20-2(6^2\div3\times2^2)]=88

3 0
3 years ago
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