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REY [17]
3 years ago
13

Which ordered pair is a solution of the equation?

Mathematics
1 answer:
uysha [10]3 years ago
5 0
Only b

apply -1 to x and it will give you y=-5


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Help!
CaHeK987 [17]

\pi+18-irrational\ because\ \pi\ is\ irrational\\\\\sqrt{25+1.75}=\sqrt{26.75}=\sqrt{\dfrac{2675}{100}}=\dfrac{\sqrt{2675}}{\sqrt{100}}=\dfrac{\sqrt{25\cdot107}}{10}\\\\=\dfrac{\sqrt{25}\cdot\sqrt{107}}{10}=\dfrac{5\sqrt{107}}{10}=\dfrac{\sqrt{107}}{2}-irrational\\\\\sqrt{3+5.5}=\sqrt{8.5}=\sqrt{\dfrac{85}{10}}=\sqrt{\dfrac{850}{100}}=\dfrac{\sqrt{850}}{\sqrt{100}}=\dfrac{\sqrt{25\cdot34}}{10}\\\\=\dfrac{\sqrt{25}\cdot\sqrt{34}}{10}=\dfrac{5\sqrt{34}}{10}=\dfrac{\sqrt{34}}{2}-irrational

\pi+\sqrt2-irrational

3 0
3 years ago
Which of the following
Lera25 [3.4K]
I’m pretty sure it’s D but I may be wrong
8 0
3 years ago
Jordie is getting balloons for his aunt's birthday party. He wants each balloon string to be 12 feet long. At the party store, s
geniusboy [140]

Answer:

216 yards

Step-by-step explanation:

You'd multiply the amount of string for each balloon (12 feet) by the 54 balloons he needs, and you get 648 feet. There are 3 feet in a yard so then you would divide 648 by 3 and get 216 yards

8 0
2 years ago
Need help on this. Don’t understand a thing and I need to get this done ASAP. If you knew please help. It would be greatly appre
matrenka [14]

Answer:

the Lateral SA is 84

The total is 1092.

Step-by-step explanation:

4 0
3 years ago
A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 2
Shalnov [3]

Answer:

The expected winnings for a person buying 1 ticket is -0.2.                  

Step-by-step explanation:

Given : A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 25 cents each, find the expected winnings for a person buying 1 ticket.

To find : What are the expected winnings?    

Solution :

There are one first prize, 2 second prize and 20 third prizes.

Probability of getting first prize is \frac{1}{20000}

Probability of getting second prize is \frac{2}{20000}

Probability of getting third prize is \frac{20}{20000}

A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each.

So, The value of prizes is

\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10

If 20000 tickets are sold at 25 cents each i.e. $0.25.

Remaining tickets = 20000-1-2-20=19977

Probability of getting remaining tickets is \frac{19977}{20000}

The expected value is

E=\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10-\frac{19977}{20000}\times 0.25

E=\frac{1000+600+200-4994.25}{20000}

E=\frac{-3194.25}{20000}

E=-0.159

Therefore, The expected winnings for a person buying 1 ticket is -0.2.

3 0
3 years ago
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