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KATRIN_1 [288]
3 years ago
7

A circular mirror is surrounded by a square metal frame the radius of the mirror is 2X the side length of the metal frame is 6X

what is the area of the metal frame
Mathematics
2 answers:
pogonyaev3 years ago
7 0

Answer:

4x^2(9−π)

Step-by-step explanation:

envision

vovangra [49]3 years ago
6 0

Answer:

Area of the metal frame is 23.43x^2.

Step-by-step explanation:

Given:

Radius of circular mirror = 2x

Side length of the metal frame = 6x

We need to find the area of the metal frame.

Solution:

First we will find the area of the whole thing.

area of the whole thing is in square shape we can say that;

area of the whole thing is equal to square of the length of the metal frame.

framing in equation form we get;

area of the whole thing = (6x)^2 = 36x^2

Now we will find the area of the circular mirror.

Since mirror is in circular form we will use area of the circle.

So area of circular mirror is equal to π times square of the radius.

framing in equation form we get;

area of the circular mirror = \pi r^2 = \pi(2x)^2 = \pi 4x^2 = 12.57x^2

Now to find the area of the metal frame surrounded my the mirror we will subtract area of the circular mirror from area of the whole thing.

framing in equation form we get;

area of the metal frame = 36x^2-12.57x^2 = 23.43x^2

Hence Area of the metal frame is 23.43x^2.

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3 years ago
Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat
nirvana33 [79]

Answer:

V = \pi r^2 h

For this case we know that r=5m represent the radius, h = 10m the height and the rate given is:

\frac{dV}{dt}= \frac{100 L}{min}

Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}

And replacing we got:

\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}

And that represent 0.127 \frac{cm}{min}

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

V = \pi r^2 h

For this case we know that r=5m represent the radius, h = 10m the height and the rate given is:

\frac{dV}{dt}= \frac{100 L}{min}

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}

And solving for \frac{dh}{dt} we got:

\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}

We need to convert the rate given into m^3/min and we got:

Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}

And replacing we got:

\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}

And that represent 0.127 \frac{cm}{min}

5 0
3 years ago
Distribute and evaluating <br> (X + 6) (x - 3)
sesenic [268]

Answer:

x^2+3x-18

Step-by-step explanation: hoped I helped

7 0
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The principal P is borrowed and the loan's future value A at time t is given. Determine the loan's simple interest rater.
Anni [7]
Interest rate = 7%

I= PRT where I is the interest earned, p is the principal, r is rate as a decimal, and t is time in years.


A - P will give us the interest earned.

12,150 - 9,000 = 3,150

3150 = (9000)(r)(5)
3150 = 45,000r
r = 0.07
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4 0
3 years ago
The equation f(x)=x−5 translated 4 units to the left is g(x)=
elixir [45]

The equation of the function g(x) is g(x) = x - 1

<h3>How to determine the equation of the function g(x)?</h3>

The given parameters are:

f(x) = x - 5

The above function f(x) is translated left by 4 units

So, we have

g(x) = f(x + 4)

This gives

f(x + 4) = x + 4- 5

Evaluate the sum

f(x + 4) = x - 1

So, we have:

g(x) = x - 1

Hence, the equation of the function g(x) is g(x) = x - 1

Read more about function transformation at:

brainly.com/question/10904859

#SPJ1

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2 years ago
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