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KATRIN_1 [288]
2 years ago
7

A circular mirror is surrounded by a square metal frame the radius of the mirror is 2X the side length of the metal frame is 6X

what is the area of the metal frame
Mathematics
2 answers:
pogonyaev2 years ago
7 0

Answer:

4x^2(9−π)

Step-by-step explanation:

envision

vovangra [49]2 years ago
6 0

Answer:

Area of the metal frame is 23.43x^2.

Step-by-step explanation:

Given:

Radius of circular mirror = 2x

Side length of the metal frame = 6x

We need to find the area of the metal frame.

Solution:

First we will find the area of the whole thing.

area of the whole thing is in square shape we can say that;

area of the whole thing is equal to square of the length of the metal frame.

framing in equation form we get;

area of the whole thing = (6x)^2 = 36x^2

Now we will find the area of the circular mirror.

Since mirror is in circular form we will use area of the circle.

So area of circular mirror is equal to π times square of the radius.

framing in equation form we get;

area of the circular mirror = \pi r^2 = \pi(2x)^2 = \pi 4x^2 = 12.57x^2

Now to find the area of the metal frame surrounded my the mirror we will subtract area of the circular mirror from area of the whole thing.

framing in equation form we get;

area of the metal frame = 36x^2-12.57x^2 = 23.43x^2

Hence Area of the metal frame is 23.43x^2.

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A.  -1/4(x-10)^2

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11. Kamala borrowed 26400 from a bank to buy a scooter at a rate of 15% per annum compounded yearly. What amount will she pay at
oee [108]
<h2>Answer </h2>

Amount (A) = P[1 + (r/100)]n

Principal (P) = ₹ 26400

Time period (n) = 2 years 4 months

Rate % (R) = 15% compounded annually

<h3>Steps </h3>

First, we will calculate Compound Interest (C.I) for the period of 2 years

A = P[1 + (r/100)]n

= 26400[1 + (15/100)]²

= 26400[(100/100) + (15/100)]²

= 26400 × 115/100 × 115/100

= 26400 × 23/20 × 23/20

= 26400 × 1.3225

= 34914

C.I. = A - P

= 34914 - 26400

= 8514

Now, we will find Simple Interest (S.I) for the period of 4 months

Principal for 4 months after C.I. for 2 years = ₹ 34,914

<h3>We know that ,</h3>

S.I = PRT/100

Here T = 4 months = 4/12 years = 1/3 years

S.I. for 4 months = (1/3) × 34914 × (15/100)

= (1/3) × 34914 × (3/20)

= 34914/20

= 1745.70

Total interest for 2 years 4 months = 8514 + 1745.70

= 10259.70

Total amount for 2 years 4 months = 26400 + 10259.70

= ₹ 36659.70

<h3>So , the correct answer is ₹ 36659.70 . </h3>

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2 years ago
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Please help ❗️❗️❗️❗️ Please! I will reward brainly
zhuklara [117]
Hey there :)

We know the distance formula is:
D = \sqrt{(x2-x1)^2+(y2-y1)^2}

1) Coordinates are: ( -10, -5 ) , ( 8 , 5 )
                                    ↓   ↓       ↓    ↓
                                    x₁ y₁     x₂   y₂
We plug in the values 
D =\sqrt{(8 -(-10))^2+(5-(-5))^2}
    ≈20.59 ≈ 20.6 (nearest tenth)

We do the same for the rest

2) Coordinates are ( 10 , 0 ) , ( -2 , 1 )
D = \sqrt{(-2-10)^2+(1-0)^2}
   ≈ 12.04 ≈ 12.0 (nearest tenth)

3) Coordinates are ( 4 , 8 ) , ( 7 , -8 )
D = \sqrt{((7-4)^2+(-8-8)^2}
   ≈ 16.27 ≈ 16.3 (nearest tenth)

4) Coordinates are ( -10, -4 ) , ( 8 , 8 )
D = \sqrt{(8-(-10))^2+(8-(-4))^2}
    ≈ 21.6 (nearest tenth)

5) Coordinates are ( 6 , -3 ) , ( -8 , 9 )
D = \sqrt{(-8-6)^2 + (9-(-3))^2}
   ≈ 18.4 (nearest tenth) 

You can find the matching below :)



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