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alex41 [277]
3 years ago
13

A six-sided die is rolled three times. what is the probability that all three rolls will be 6?

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
6 0

you have a 1/6 probability of rolling a 6

 so for 3 6's it would be

1/6 x 1/6 x 1/6 = 1/216

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Sanya noticed that the temperature was falling at a steady rate of 1.4 degrees every hour after the time that she first checked
Snezhnost [94]

Answer:

21 ÷ 1.4

Step-by-step explanation:

Sanya noticed that the temperature was falling at a steady rate of 1.4 degrees every hour.

The temperature had fallen 21 degrees, so it passed

21:1.4=210:14=30:2=15

hours after she had first checked the thermometer.

She had first checked the temperature at 3 p.m.

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3 years ago
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Karen is planting a tree. She wants to use two guy wires to stabilize the tree. If Karen places the guy wires 8 feet up the trun
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15 feet of wire (I’m pretty sure?)
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6. As part of their employee benefits, all workers at Light and Power Electric Company
Semenov [28]

Answer:

  $1769.06

Step-by-step explanation:

The sum of Mia's three highest salaries is ...

  $92,000 +94,800 +96,250 = $283,050

so the average is ...

  $283,050/3 = $94,350

Her pension is then ...

  0.01875 × $94,350 = $1769.06

_____

<em>Additional comment</em>

This is equivalent to the total of those salaries, divided by 160.

  T/3 × 0.01875 = T × (0.01875/3) = T × 0.00625 = T/160

Sometimes, there are simpler ways to calculate things like this.

8 0
3 years ago
Find the interval(s) where the function is increasing and the interval(s) where it is decreasing. (Enter your answers using inte
Mashcka [7]

Answer:

f'(x) > 0 on (-\infty ,\frac{1}{e}) and f'(x)<0 on(\frac{1}{e},\infty)

Step-by-step explanation:

1) To find and interval where any given function is increasing, the first derivative of its function must be greater than zero:

f'(x)>0

To find its decreasing interval :

f'(x)

2) Then let's find the critical point of this function:

f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}[6-2^{2x}]=\frac{\mathrm{d} }{\mathrm{d}x}[6]-\frac{\mathrm{d}}{\mathrm{d}x}[2^{2x}]=0-[ln(2)*2^{2x}*\frac{\mathrm{d}}{\mathrm{d}x}[2x]=-ln(2)*2^{2x}*2=-ln2*2^{2x+1\Rightarrow }f'(x)=-ln(2)*2^{2x}*2\\-ln(2)*2^{2x+1}=-2x^{2x}(ln(x)+1)=0

2.2 Solving for x this equation, this will lead us to one critical point since x'  is not defined for Real set, and x''=\frac{1}{e}≈0.37 for e≈2.72

x^{2x}=0 \ni \mathbb{R}\\(ln(x)+1)=0\Rightarrow ln(x)=-1\Rightarrow x=e^{-1}\Rightarrow x\approx 2.72^{-1}x\approx 0.37

3) Finally, check it out the critical point, i.e. f'(x) >0 and below f'(x)<0.

8 0
3 years ago
PLLLLLLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
LenaWriter [7]
The answer to this question is 23. How you get this is by adding all the sides like this: 2n+6+135+151+140+63=540. Then you just solve the equation.
8 0
4 years ago
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