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fiasKO [112]
2 years ago
7

Given parallelogram ABCD with c(5,4), find the coordinates of A if the diagonals intersect at (2,7)

Mathematics
1 answer:
vladimir1956 [14]2 years ago
7 0

Answer: (-1, 10)

Step-by-step explanation:

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38.3 cm<br> Р<br> 0 12.6 cm R
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Answer:

Step-by-step explanation: F 50.9 cm (H 25.7 cm. G 46.3 cm. -38.3 cm. G 46.3 cm. 921.3 cm. Ø 12.6em Å ... Р. 3 - с. 2, +6:48 348 р. 8. Find the distance between P(2, 8) and Q15, 3). F9 ... REVIEW VOCABULARY!!!!! R=0 tre of the two angles. Atab=180. 2 ДО - Чx 49.

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2 years ago
Write an expression equal to 11³​
NikAS [45]

Answer:

11x11x11=11³

Step-by-step explanation:

11 to the third means 11 times itself 3 times

3 0
2 years ago
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In a nursery class of 18 pupils, the average is
melamori03 [73]

Answer:

The sum of the age of pupils is 81

Step-by-step explanation:

Let sum of age of 18pupils = x

Average ages = 4.5

Average = total/no. of pupil

4.5 = x/18

x = 81

8 0
3 years ago
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You work at an ice-cream shop. One of your jobs is to order new ice-cream cones. You pick the cone that is 5 inches high and has
Taya2010 [7]
We have that
the Volume of cone=(1/3)*B*h
B=the area of the base
h= the height of the cone
D=3.5 in-----------------> r=D/2=1.75 in
h=5 in
B=pi*r²---------> 3.14*1.75²=9.616 in²
V=(1/3)*9.616*5=48.08 in³--------> 48 in³

the answer is 48 in³
5 0
3 years ago
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Dwayne drove 18 miles to the airport to pick up his father and then returned home. On the return trip he was able to drive an av
Nesterboy [21]

Answer:

30 mph

Step-by-step explanation:

Let d = distance (in miles)

Let t = time (in hours)

Let v = average speed driving <u>to</u> the airport (in mph)

⇒ v + 15 = average speed driving <u>from</u> the airport (in mph)

Using:  distance = speed x time

\implies t=\dfrac{d}{v}

Create two equations for the journey to and from the airport, given that the distance one way is 18 miles:

\implies t=\dfrac{18}{v}  \ \ \textsf{and} \ \  t=\dfrac{18}{v+15}

We are told that the total driving time is 1 hour, so the sum of these expressions equals 1 hour:

\implies \dfrac{18}{v} +\dfrac{18}{v+15}=1

Now all we have to do is solve the equation for v:

\implies \dfrac{18(v+15)}{v(v+15)} +\dfrac{18v}{v(v+15)}=1

\implies \dfrac{18(v+15)+18v}{v(v+15)}=1

\implies 18(v+15)+18v=v(v+15)

\implies 18v+270+18v=v^2+15v

\implies v^2-21v-270=0

\implies (v-30)(v+9)=0

\implies v=30, v=-9

As v is positive, v = 30 only

So the average speed driving to the airport was 30 mph

(and the average speed driving from the airport was 45 mph)

8 0
2 years ago
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