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Schach [20]
3 years ago
13

Miguel paid a total of $12,000 for stock that was $8 per share. If he sold all his shares for $15,000, how much profit on each s

hare did he make?
a.
$2
b.
$8
c.
$10
d.
$12
Mathematics
2 answers:
Vitek1552 [10]3 years ago
7 0

Answer:

Option A.

Step-by-step explanation:

Miguel paid the total amount to purchase the shares = $12000

Cost of one share = $8

So, number of shares purchased = \frac{\text{Total amount paid}}{\text{Price of one share}}

= \frac{12000}{8}

= 1500

Selling price of 1500 shares = $15000

Since profit = Selling price - Cost price

So, net profit = $15000 - $12000

                     = $3000

Profit per share = \frac{\text{Total profit}}{\text{Number of shares sold}}

= \frac{3000}{1500}

= $2

Therefore, Option A. will be the answer.

Fofino [41]3 years ago
3 0
The answer for this question is a) 2$

He bought 1500 shares (12000/8)
and sold all of them for 15000 which means that he sold each share for 10$ (15000/1500)
So he got got a profit of 2$ (10$-8$)
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Can anyone help me with the answer for number 4
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Answer:

b

Step-by-step explanation:

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JK = KL ← substitute values

6x = 3x + 3 ( subtract 3x from both sides )

3x = 3 ( divide both sides by 3 )

x = 1

Hence

JK = 6x = 6 × 1 = 6

KL = 3x + 3 = (3 × 1) + 3 = 3 + 3 = 6

JL = 6 + 6 = 12

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4 years ago
Which of the following is the correct expansion of (3x-y)2
GREYUIT [131]
6x-2y (I believe so)
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3 years ago
(5x - 2y)^3<br> Expand using Bionomial Theorum. Show steps, please.
tatyana61 [14]

Answer:

125x³ − 150x²y + 60xy² − 8y³

Step-by-step explanation:

(5x − 2y)³

₃C₀ (5x)³ (-2y)⁰ + ₃C₁ (5x)² (-2y)¹ + ₃C₂ (5x)¹ (-2y)² + ₃C₃ (5x)⁰ (-2y)³

(1) (125x³) (1) + (3) (25x²) (-2y) + (3) (5x) (4y²) + (1) (1) (-8y³)

125x³ − 150x²y + 60xy² − 8y³

7 0
3 years ago
Solve the following system of equations.
vodomira [7]

Answer:

a = 6/5

b = 7/8

c = 1/5

Step-by-step explanation:

We want to make two of these equations be in terms of the same variable, so let's solve the first and third  in terms of b.  

5a-24b=-15 -> -3 + 24b/5 = a

48b+35c = 49 -> 49/35 - 48b/35 = 7/5 - 48b/35 = c

Now we can replace the a and c in the second equation and solve for b.

10a+45c=21

10(-3+24b/5)+45(7/5 - 48b/35) = 21

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7 0
3 years ago
Which table represents the same linear relationship as y = 3x - 2?
Trava [24]

Answer:

Table 4  represents the same linear expression  as y = 3 x - 2.

Step-by-step explanation:

Here, the given expression is y = 3 x -2

So now check the any random pair of each table by putting in the given equation.

<u>TABLE 1 :  (2,-5)</u>

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y = 3x -2  ⇒  3 = 3(0) -2

or, 3 = -2 , NOT POSSIBLE

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y = 3x -2  ⇒  2 = 3(1) -2

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<u>TABLE 4 :  (1,1)</u>

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checking for (2,4)

4 = 3(2) - 2  ⇒4 = 4 POSSIBLE

Here, table 4 satisfies the given points in the expression y = 3x -2

Hence, it represents the same linear expression .

3 0
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