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4 years ago

What is the answer to -6+5b=6b-7

2 answers:

8 0

Remember
ou can do anything to an equaiotn as long as you do it to both sides
try to isolate variable and get 1 of it

-6+5b=6b-7
subtract 5b from both sides
-6=b-7
add 7
1=b

Hitman42 [59]4 years ago

5 0

5b-6=6b=6b-7-6b
-b-6= -7
-b-6+6= -7+6
-b= -1
-b/-1= -1/-1
b= 1

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The parallelogram shown below has an area of 404040 units^2 2 squared.

TEA [102]

Question:

The parallelogram shown below has an area of 40 units squared.

Find the missing base.

Answer:

See Explanation Below

Step-by-step explanation:

The question is incomplete as the diagram which shows the dimension of the parallelogram is not attached.

However, I'll give a general explanation on how to get the base of the parallelogram. If you follow this explanation, you'll get the right answer regarding your question.

The area of a parallelogram is calculated as thus.

Area = Base * Height

Given that the area = 40 units²

Let's assume the height of the parallelogram is 10 unit.

All you need to do is to plug in these values in the formula above..

Area = Base * Height becomes

40 = Base * 10

Divide both sides by 10

40/10 = Base * 10/10

4 = Base

Hence, Base = 4 units

Or take for instance the height is 5 units.

You'll still follow the simple steps as it is above.

Area = Base * Height becomes

40 = Base * 5

Divide both sides by 5

40/5 = Base * 5/5

8 = Base

Hence, Base = 8 units

8 0

3 years ago

(Will mark brainliest) A box shaped like a rectangular prism is 14.5 centimeters long, 4 centimeters wide and 3.5 centimeters hi

slamgirl [31]

I don't know the answer please

5 0

3 years ago

Assume that both populations are normally distributed. a) Test whether mu 1 not equals mu 2 at the alpha equals 0.05 level of s

Radda [10]

Answer:

$(16.2-14.1) -2.03 \sqrt{\frac{4.5^2}{19} +\frac{3.1^2}{19}} = -0.445$

$(16.2-14.1) +2.03 \sqrt{\frac{4.5^2}{19} +\frac{3.1^2}{19}} = 4.645$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$n_1 = 19$ sample size 1

$n_2 = 19$ sample size 2

$\\bar X_1 = 16.2$ sample mean for group 1

$\\bar X_2 = 14.2$ sample mean for group 2

$s_1 = 4.5$ sample deviation for group 1

$s_2 = 3.1$ sample deviation for group 2

Solution to the problem

For this case the confidence interval is given by:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}$

And the degrees of freedom are given by:

$df = n_1 +n_2 -2 = 19+19 -2= 36$

We want a 95% of confidence o then the significance level is 1-0.95 =0.05 and $\alpha/2 = 0.025$ if we find a critical value in the t distribution with 36 degrees of freedom we got: