Sorry for being late but it’s go up 1 and right 9. ( you can remember this in the way that 1 is going up and 9 is going right, if it’s negative it would be -1 going down and -9 going left) hope this helps!
Degree is exponent, so 5th degree
difference of 2 perfect squares
a^2-b^2=(a-b)(a+b)
t^2-5^2=(t-5)(t+5)
2nd one
complete square
take 1/2 of linear coefient and square it
-6/2=-3, (-3)^2=9
add that to both sides
x^2-6x+9=-8+9
x^2-6x+9=1
factor
(x-3)^2=1
sqrt
take neg and pos root
x-3=+/-1
add 3
x=3+/-1
x=3+1 or x=3-1
x=4 or 2
3rd option
To look for the area of a sector of a circle, the following formula is used:
Area = ( n / 360 ) * pi * r^2
Where: n = measure of arc in degrees
pi = 3.1416
r = radius
Since we are already given all of the needed parts of the formula, direct substitution is done, as shown below:
Area = ( n / 360 <span>) * pi * r^2
</span>Area = ( 45 / 360 ) *3.1416 * (8)^2
Area = 25.133 in^2
Therefore, the area of the sector of the circle is 25.133 sq. in.
Answer:
11270 cm2
Step-by-step explanation:
A = 2(wl+hl+hw)
= 2(47•59+27•59+27•47)
= 11270
