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Stella [2.4K]
3 years ago
5

The points plotted below are on the graph of a polynomial. In what range of x-values must the polynomial have a root? Check all

that apply.
A. 2.5 to 3.5
B. 3.5 to 4.5
C. 5.5 to 6.5
D. -2.5 to -1.5
E. -1.5 to -0.5
F. 1.5 to 2.5

Mathematics
1 answer:
Annette [7]3 years ago
4 0
"2.5 to 3.5", "5.5 to 6.5", "-1.5 to -0.5" and "1.5 to 2.5" are the range of x-values among the following choices given in the question for which <span>the polynomial must have a root. The correct options among all the options that are given in the question are options "A", "C", "E" and "F". I hope that the answer has come to your help.</span>
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which ordered pair is a solution of the equation y=4x-7 A. only (2,1) B. only (4,9) C. Both (2,1) and ( 4,9) D Neither
Sphinxa [80]

Hey there! :)

Answer:

C. Both (2,1) and (4,9)

Step-by-step explanation:

To solve this question, simply plug in the coordinates of answer choices given into y = 4x - 7:

A.

1 = 4(2) - 7

1 = 8 - 7

1 = 1. A is correct.

B.

9 = 4(4) - 7

9 = 16 - 7

9 = 9. B is correct.

Therefore, the correct answer is C. Both (2,1) and (4,9) are solutions to this equation.

7 0
3 years ago
6th-grade math, fill out the table! :)
Svetradugi [14.3K]

Answer:

21 wins, table is attached.

Step-by-step explanation:

The ratio of 7 wins to 2 losses is 7:2. A ratio is just saying that every time one value is increased by 7, the other is increased by 2.

So we can fill out the table, in every iteration wins increases by 7 and losses increases by 2.

When we fill this out, we find that when losses is 6, wins is 21, so when you have 2 losses you have 21 wins.

Hope this helped!

4 0
3 years ago
Write an equation for a circle with a diameter that has endpoints at (–4, –7) and (–2, –5). Round to the nearest tenth if necess
Zinaida [17]

since we know the endpoints of the circle, we know then that distance from one to another is really the diameter, and half of that is its radius.

we can also find the midpoint of those two endpoints and we'll be landing right on the center of the circle.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[-2-(-4)]^2+[-5-(-7)]^2}\implies d=\sqrt{(-2+4)^2+(-5+7)^2} \\\\\\ d=\sqrt{2^2+2^2}\implies d=\sqrt{2\cdot 2^2}\implies d=2\sqrt{2}~\hfill \stackrel{~\hfill radius}{\cfrac{2\sqrt{2}}{2}\implies\boxed{ \sqrt{2}}} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-4}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-5})\qquad \qquad \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{-2-4}{2}~~,~~\cfrac{-5-7}{2} \right)\implies \left( \cfrac{-6}{2}~,~\cfrac{-12}{2} \right)\implies \stackrel{center}{\boxed{(-3,-6)}} \\\\[-0.35em] ~\dotfill

\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{-3}{ h},\stackrel{-6}{ k})\qquad \qquad radius=\stackrel{\sqrt{2}}{ r} \\[2em] [x-(-3)]^2+[y-(-6)]^2=(\sqrt{2})^2\implies (x+3)^2+(y+6)^2=2

4 0
3 years ago
Read 2 more answers
The volume of a right triangular prism is 72 cubic feet. The height of the prism is 9 feet. The triangular base is an isosceles
Mariulka [41]

Answer:

Step-by-step explanation:

volume = area of base * height = area of base * 9 = 72

-> area of base = 72/9 = 8

let a,b,c be the length of sides of isosceles right triangle base

we have a = b and a*b/2 = 8 ft2

-> a*a/2 = 8ft2

-> a*a = 16

-> a=4ft=b

have c^2 = a^2 + b^2 = 16 +16 = 32

-> c = \sqrt{32} = 5.656 ft

Since i dont know that is DF, i calculate both a,b and c

3 0
3 years ago
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Plz i need this rn
Lunna [17]

Answer:

well i feel like she walked the whole thing

because one tenth is 0.1 miles and she walked that distance

Step-by-step explanation:

4 0
3 years ago
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