By what number should 1356 be divided to get 31 as quotient and 32 as a remainder?
1 answer:
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The answer is: " 11 " .
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→ " x = 11 " .
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Explanation:
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Set up the ratio/ proportion as a fraction:
6 cm / 48 cm = 5 cm / (3x + 7) ;
→ The "cm" units cancel out; since: "cm/cm = 1 " ;
→ The "6/48" = "(6 ÷ 6) / (48 ÷ 6) = " 1/8 " ;
→ Rewrite as:
;
Now, we can "cross-multiply" :
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<u>Note</u>:
; 
;
{b
; d } .
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As such:
1 * (3x + 7) = 8 * 5 ;
→ 3x + 7 = 40 ;
Subtract "7" from each side of the equation:
→ 3x + 7 − 7 = 40 <span>− 7 ;
</span>
to get:
→ 3x = 33 ;
Now, divide each side of the equation by "3" ;
to isolate "x" on one side of the equation; & to solve for "x" ;
→ 3x / 3 = 33 / 3 ;
to get:
____________________________________________________
→ " x = 11 " .
____________________________________________________
→ The answer is: " 11 " .
____________________________________________________
____________________________________________________
→ " x = 11 " .
____________________________________________________
Explanation:
____________________________________________________
Set up the ratio/ proportion as a fraction:
6 cm / 48 cm = 5 cm / (3x + 7) ;
→ The "cm" units cancel out; since: "cm/cm = 1 " ;
→ The "6/48" = "(6 ÷ 6) / (48 ÷ 6) = " 1/8 " ;
→ Rewrite as:
Now, we can "cross-multiply" :
__________________________________________________
<u>Note</u>:
{b
__________________________________________________
As such:
1 * (3x + 7) = 8 * 5 ;
→ 3x + 7 = 40 ;
Subtract "7" from each side of the equation:
→ 3x + 7 − 7 = 40 <span>− 7 ;
</span>
to get:
→ 3x = 33 ;
Now, divide each side of the equation by "3" ;
to isolate "x" on one side of the equation; & to solve for "x" ;
→ 3x / 3 = 33 / 3 ;
to get:
____________________________________________________
→ " x = 11 " .
____________________________________________________
→ The answer is: " 11 " .
____________________________________________________
Answer:
Step-by-step explanation:
GIVEN: A bicycle training wheel has a radius of . The bicycle wheel has a radius of
.
TO FIND: Approximately how much smaller, in square inches, is the area of the training wheel than the area of the regular wheel.
SOLUTION:
radius of bicycle wheel
area of bicycle wheel
putting value,
area of bicycle wheel
radius of bicycle training wheel
area of bicycle training wheel
putting value,
area of bicycle wheel
difference in area of bicycle wheel and bicycle training wheel
hence the training wheel is smaller than regular wheel