Answer:
The first one I believe
Step-by-step explanation:
Answer:
By the Central Limit Theorem, both would be approximately normal and have the same mean. The difference is in the standard deviation, since as the sample size increases, the standard deviation decreases. So the SRS of 600 would have a smaller standard deviation than the SRS of 200.
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean
and standard deviation
, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
and standard deviation
.
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
For the sampling distribution of size n of a sample proportion p, the mean is p and the standard deviation is 
Differences between SRS of 200 and of 600
By the Central Limit Theorem, both would be approximately normal and have the same mean. The difference is in the standard deviation, since as the sample size increases, the standard deviation decreases. So the SRS of 600 would have a smaller standard deviation than the SRS of 200.
Answer:
( x+1)^2 + (y+2)^2 = 25
The center is (-1, -2) and the radius is 5
Step-by-step explanation:
x^2 + 2x + y^2 + 4y = 20
Complete the square
2/2 =1 1^2 =1 so add 1 for x 4/2 =2 2^2 = 4 so add 4 for y
x^2 +2x +1 +y^2 +4y+4 = 20 +1 +4
( x+1)^2 + (y+2)^2 = 25
(x+1) ^2 + (y+2)^2 = 5^2
(x - -1) ^2 + (y - -2)^2 = 5^2
This is in (x-h)^2 + (y-k)^2 = r^2 form where (h,k) is the center and r is the radius
The center is (-1, -2) and the radius is 5
Answer:
x = 3/8 (but the fraction is negative.)
Decimal form if needed.
x = - 0.375